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PHP创建验证码时,参数的作用

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Release: 2016-06-13 12:41:47
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PHP创建验证码时,求一个参数的作用?

<br />
for($i=0;$i<$num;$i++){ <br />
	$x=rand(1,8)+$imagewidth*$i/4;<br />
	$y=rand(1,$imageheight/4);<br />
	$font = ImageColorAllocate($im, rand(100,255),rand(0,100),rand(100,255)); // 生成随机颜色 <br />
	$authnum=rand(1,9); <br />
	$vcodes.=$authnum; <br />
	imagestring($im, 15, $x, $y, $authnum, $font); <br />
} <br />
Copy after login

在这个循环语句里,求$num的作用?

因为imagestring()函数的作用:向图像中添加数字。我认为$num肯定是用来限制向图像中添加数字的个数,
但是更改$num=4,$num=15 或者其他数字,图像中显示的仍然是4个字符。

还有我想弱弱的问一下,通过post和get传递的参数,比如login?id=2&value=3,这个id,value通过
$_POST或者$_GET获取之后,id和value的值是整数还是字符呀!

不想验证了,太麻烦,就大侠指教!!!

PHP 验证码 $_POST[]
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