关于json_decode对象？
class Demp{
public $a=10;
function test()
{
echo "aaa";
}
}
$p=new Demp();
$c=json_encode($p);
//json_decode($c)->test();
?>
打印json_decode($c)->a 可以
无法调用test()是因为json无法保存类型的原因吗？
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