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mysql_fetch_arry()返回的变量是字符串,怎么用超链接显示到页面上?

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Release: 2016-06-13 12:25:28
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mysql_fetch_arry()返回的变量是字符串,如何用超链接显示到页面上??
mysql_fetch_arry()返回的变量是字符串,这个字符串是一个文件的路径,如何用超链接显示到页面上??用户可以直接点击这里超链接就可以打开这个文件。
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是同一页面接收的数据么?
------解决思路----------------------
输出用html的a标签。
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<br />$str = mysql_fetch_array($rs);<br />echo '<a herf="'. $str .'">超链接到文件</a>';<br />
Copy after login

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加个标记。
然后需要加域名。
------解决思路----------------------
echo '
herf="'. $str .'">超链接到文件';

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