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类的静态方法在继承中的使用,不大明白,self和this如何转换

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Release: 2016-06-13 12:04:14
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类的静态方法在继承中的使用,不大明白,self和this怎么转换?

<?php<br />class A  //核心<br />{<br />	public $db;<br />	public function __construct(){<br />		$this->db=new B();	<br />	}<br />	public function find(){<br />		return  $this->db->b1();	<br />	}<br />}<br />class B  //数据库<br />{<br />	public function b1(){<br />		return true;<br />	}<br />	public function b2(){<br />		return false;<br />	}<br />}<br />//**********分隔符***********<br />class C extends A //第三方类<br />{<br />	 static function test(){<br />		return self::find();	<br />	}<br />}<br />//当前文件<br />if(C::test()){<br />	echo 'OK';	<br />}<br />?>
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这个文件执行是错的,
只能修改核心和当前文件部分,
我想要当前文件部分那样简短的写法,
不想用$c=new C()
if($c->test()) 这样的写法?

上面错误的原因是
静态方法调用find的时候,
A类的find里有$this对象,就报错了
请问我的想法能不能实现呢
------解决方案--------------------
虽然不符合规则,但也不是不可以
或许以后还会改变规则呢?自己给自己套枷锁总是没道理的
class A  //核心<br />{<br />    private static $_Instance;<br />    public $db;<br />    public function __construct(){<br />        $this->db=new B();   <br />    }<br />    public function find(){<br />        if(empty(self::$_Instance)) self::$_Instance = new self();<br />        return  self::$_Instance->db->b1();   <br />    }<br />}<br />class B  //数据库<br />{<br />    public function b1(){<br />        return true;<br />    }<br />    public function b2(){<br />        return false;<br />    }<br />}<br />//**********分隔符***********<br />class C extends A //第三方类<br />{<br />   static function test(){<br />     return self::find();   <br />   }<br />}<br /><br />error_reporting(E_ALL ^ E_STRICT);<br /><br />//当前文件<br />if(C::test()){<br />    echo 'OK';   <br />}
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OK

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