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求高手 拯救小弟我PHP变量后面带[]是什么 意思

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Release: 2016-06-13 11:36:36
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求高手 拯救我PHP变量后面带[]是什么 意思
我就贴上关键代码

<br />foreach ($logData as $key => $data) {<br />			$kItem[] = $key;//这里变量后面的[]是什么<br />			$dItem[] = $data;<br />			$cshu++;<br />			if($cshu == 8) $dItem[] = "i";<br />		}<br />		$field = implode(',', $kItem);<br />		$values = "'" . implode("','", $dItem) . "'";<br />		$this->db->query("INSERT INTO " . DB_PREFIX . "blog ($field) VALUES ($values)");
Copy after login


循环读出数组 循环到第八个数据的时候 修改 $dItem[]的值为i 但是在写入数据的时候 这个I却是多出的
SQL语句执行错误:INSERT INTO emlog_blog (title,alias,content,excerpt,author,sortid,date,top,allow_remark,allow_tb,hide,password) VALUES ('dsa','','das','','39','-1','1380936471','n','i','y','y','n','')
Column count doesn't match value count at row 1

报错的原因是因为多出了一个I值 我想把I前面的N替换掉的 但是不知道为什么他就是不能替换值
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