求人解释下这段代码,关于引用传递,该如何处理
Release： 2016-06-13 10:21:47
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求人解释下这段代码,关于引用传递
PHP code<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->function demo(&$num){ echo $num++."<br>"; } $num=0; demo($num); demo($num); demo($num); demo($num);Copy after login
结果为:
0
1
2
3
可以详细点吗,最好能有步骤
------解决方案--------------------很简单，你只要把&弄懂就行了。
&$num 是引用。
执行4次也就运算后$num自身四次加1。
所以输出0 1 2 3
你也可以把++$num试试。
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