Home > Backend Development > Python Tutorial > Why Does My Flask View Raise a TypeError: 'bool' Object is Not Callable?

Why Does My Flask View Raise a TypeError: 'bool' Object is Not Callable?

Patricia Arquette
Release: 2024-12-17 07:49:25
Original
371 people have browsed it

Why Does My Flask View Raise a TypeError: 'bool' Object is Not Callable?

Flask View Raising TypeError: 'bool' Object Not Callable

When developing Flask applications, you may encounter an error stating "TypeError: 'bool' object is not callable." This typically occurs when a view function returns a boolean value, which is not a valid response in Flask.

Understanding Flask View Responses

Flask views can return one of the following types of responses:

  • String
  • Response object or subclass
  • Tuple of (string, status, headers) or (string, status)
  • Valid WSGI application

The Issue

In the provided case, the view function returns True when a user successfully logs in. However, a boolean value is not a valid response type in Flask. As a result, Flask interprets the returned value as a WSGI application, leading to the error.

Solution

To resolve this issue, ensure that your view function returns one of the accepted response types. In this case, you can simply return a Response object to indicate a successful login:

from flask import Response

@app.route('/login', methods=['POST'])
def login():
    username = request.form['username']
    user = User.query.filter_by(username=username).first()

    if user:
        login_user(user)
        return Response(status=200)  # Successful login

    return Response(status=401)  # Unsuccessful login
Copy after login

By returning a Response object with the appropriate status code, you can resolve the TypeError and ensure that your view function handles user login correctly.

The above is the detailed content of Why Does My Flask View Raise a TypeError: 'bool' Object is Not Callable?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template