Imagine your Python package contains template text files that you want to access from within your program. When specifying the path to these files, it becomes necessary to handle the package structure.
If backward compatibility is not a concern (i.e., you are using Python 3.9 or above), leverage the importlib.resources module.
from importlib import resources as impresources from . import templates inp_file = impresources.files(templates) / 'temp_file' with inp_file.open("rt") as f: template = f.read()
For Python versions below 3.9, consider using the pkg_resources module from the setuptools distribution.
import pkg_resources # Could be a dot-separated package/module name or a "Requirement" resource_package = __name__ resource_path = '/'.join(('templates', 'temp_file')) # Do not use os.path.join() template = pkg_resources.resource_string(resource_package, resource_path) # or for a file-like stream: template = pkg_resources.resource_stream(resource_package, resource_path)
Locate your templates within the package hierarchy:
<your-package> +--<module-asking-for-the-file> +--templates/ +--temp_file
Reference the template file using either method:
Option 1 (importlib.resources):
from . import templates inp_file = impresources.files(templates) / 'temp_file'
Option 2 (pkg_resources):
resource_path = '/'.join(('templates', 'temp_file')) template = pkg_resources.resource_string(__name__, resource_path)
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