Home > Web Front-end > JS Tutorial > How Do I Efficiently Convert Between JavaScript Strings and ArrayBuffers Using TextEncoder and TextDecoder APIs?

How Do I Efficiently Convert Between JavaScript Strings and ArrayBuffers Using TextEncoder and TextDecoder APIs?

DDD
Release: 2024-12-06 08:06:12
Original
152 people have browsed it

How Do I Efficiently Convert Between JavaScript Strings and ArrayBuffers Using TextEncoder and TextDecoder APIs?

Converting Between Strings and ArrayBuffers

Storing data in localStorage often requires converting between JavaScript strings and ArrayBuffers for optimal storage and retrieval. Let's explore a widely accepted technique for efficiently performing this conversion.

TextEncoder: A Modern Solution

With the advent of new browser specs, the TextEncoder API has emerged as the standardized way to convert between strings and typed arrays. The TextEncoder interface represents an encoder for a specific character encoding, such as UTF-8. It takes a stream of code points (essentially characters) as input and emits a stream of bytes in the specified encoding.

Using TextEncoder

To use TextEncoder, create an instance with the following syntax:

var encoder = new TextEncoder(); 
Copy after login

To convert a JavaScript string to an ArrayBuffer, use the encode() method:

var encodedArray = encoder.encode("Your string here"); 
Copy after login

Decoding ArrayBuffers to Strings

You can decode an ArrayBuffer back to a string using the TextDecoder API:

var decoder = new TextDecoder();
var decodedString = decoder.decode(encodedArray);
Copy after login

Supported Encodings

As of the latest browser implementations, TextEncoder only supports the UTF-8 encoding for security and compatibility reasons. However, this should suffice for most practical applications.

The above is the detailed content of How Do I Efficiently Convert Between JavaScript Strings and ArrayBuffers Using TextEncoder and TextDecoder APIs?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template