Detecting loops in linked lists is a classic interview question that requires a sophisticated understanding of data structures and algorithms. We present a meticulous solution to this problem using Floyd's cycle-finding algorithm.
Floyd's algorithm employs two references, one advancing one step at a time, and the other advancing two steps at a time. This differential speed ensures that if there is a loop in the list, the two references will eventually meet.
Here's a step-by-step breakdown of the algorithm:
The following Java function implements Floyd's algorithm:
<code class="java">public static boolean hasLoop(Node first) { if (first == null) // List does not exist, no loop return false; Node slow, fast; // Create two references slow = fast = first; // Point both to the start of the list while (true) { slow = slow.next; // 1 hop if (fast.next != null) fast = fast.next.next; // 2 hops else return false; // Next node null -> no loop if (slow == null || fast == null) // If either hits null, no loop return false; if (slow == fast) // If the two ever meet, we have a loop return true; } }</code>
This algorithm has a constant space complexity, as it uses only two references, and a reasonable time complexity of O(n), where n is the number of nodes in the list.
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