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Phone List(HDOJ-1671)(tire树)

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Release: 2016-06-13 09:05:03
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Phone List(HDOJ-1671)(tire树)

正解是字典树,运用链表实现的一种数据结构,构建 方式和紫书上的二叉树差不多。因为这道题的内存给的比较紧,所以需要解决内存问题,但是如果递归释放内存会导致效率低下,解决方案是开一个内存池(数组),每次更新下标就可以重复利用了。

 

#include<cstdio>
#include<cstring>
#include<iostream>
#include
using namespace std;
int T,n,k;
struct pa{
    char s[15];
    int len;
};
bool cmp(pa a,pa b){
    return a.len>b.len;
}
struct trie{
    trie *next[15];
};
trie *root;
trie all_trie[1000000];
bool built(char *s,int len) {
    bool ok = true;
    trie *p = root, *q;
    for(int i=0;i<len;i++){ id="s[i]-'0';" int="" p-="">next[id]==NULL) {
            ok = false;
            q = &all_trie[k++];
            for(int j=0;j<10;j++) q->next[j] = NULL;
            p->next[id] = q;
            p = p->next[id];
        }
        else {
            p = p->next[id];
        }
    }
    return ok;
}
int main(){
    scanf("%d",&T);
    while(T--){
        scanf("%d",&n);
        pa s[10005];
        k = 0;
        bool ok = true;
        root = &all_trie[k++];
        for(int i=0;i<10;i++) root->next[i] = NULL;
        for(int i=0;i<n;i++){ .len="strlen(s[i].s);" else="" i="0;i<n;i++)" int="" ok="false;" pre="" return=""><p> </p></n;i++){></len;i++){></algorithm></iostream></cstring></cstdio>
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