Home > Web Front-end > JS Tutorial > How javaScript generates xmlhttp_javascript tips

How javaScript generates xmlhttp_javascript tips

WBOY
Release: 2016-05-16 17:08:54
Original
1324 people have browsed it
Copy code The code is as follows:

function ajaxFunction(){
var xmlHttp;
try { // Firefox, Opera 8.0, Safari
xmlHttp = new XMLHttpRequest();
}
catch (e) {
try {// Internet Explorer
xmlHttp = new ActiveXObject("Msxml2 .XMLHTTP");
}
catch (e) {
try {
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
catch (e) {
}
}
}

return xmlHttp;
}
Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template