Home > Database > Mysql Tutorial > SQL Tuning Advisor使用实例

SQL Tuning Advisor使用实例

WBOY
Release: 2016-06-07 17:26:58
Original
878 people have browsed it

在Oracle 10g之前,想要优化一个sql语句是比较麻烦,但是在Oracle 10g这个版本推出的SQL Tuning Advisor这个工具,能大大减少sql

在Oracle 10g之前,想要优化一个sql语句是比较麻烦,但是在Oracle 10g这个版本推出的SQL Tuning Advisor这个工具,能大大减少sql调优的工作量,不过要想使用SQL Tuning Advisor,一定要保证你的优化器是CBO模式。

1.首先需要创建一个用于调优的用户bamboo,并授予advisor给创建的用户

SQL> create user bamboo identified by bamboo;
User created.
SQL> grant connect,resource to bamboo;
Grant succeeded.
SQL> grant advisor to bamboo;
Grant succeeded.
 
2.创建用户做测试的2张表,大表里面插入500万条数据,小表里面插入10万条数据,其创建方法如下
SQL> create table bigtable (id number(10),name varchar2(100));
Table created.
 
SQL> begin
  2  for i in 1..5000000 loop
  3  insert into bigtable values(i,'test'||i);
  4  end loop;
  5  end;
  6  /
 
PL/SQL procedure successfully completed.
 
SQL> commti;
 
SQL> create table smalltable (id number(10),name varchar2(100));
Table created.
 
SQL> begin
  2  for i in 1..100000 loop
  3  insert into smalltable values(i,'test'||i);
  4  end loop;
  5  end;
  6  /
 
PL/SQL procedure successfully completed.
 
SQL> commti;
 
3.然后对bigtable和smalltable做一个等连接查询,然后跟踪其执行计划
SQL> select a.id,a.name,b.id,b.name from bigtable a,smalltable b where a.id=b.id and a.id=40000;
 
        ID NAME                                            ID NAME
---------- ---------------------------------------- ---------- ----------------------------------------
    40000 test40000                                    40000 test40000
 

Execution Plan
----------------------------------------------------------
Plan hash value: 1703851322
 
---------------------------------------------------------------------------------
| Id  | Operation          | Name      | Rows  | Bytes | Cost (%CPU)| Time    |
---------------------------------------------------------------------------------
|  0 | SELECT STATEMENT  |            |  839 |  106K|  3656  (5)| 00:00:44 |
|*  1 |  HASH JOIN        |            |  839 |  106K|  3656  (5)| 00:00:44 |
|*  2 |  TABLE ACCESS FULL| SMALLTABLE |    5 |  325 |    71  (3)| 00:00:01 |
|*  3 |  TABLE ACCESS FULL| BIGTABLE  |  173 | 11245 |  3584  (5)| 00:00:44 |
---------------------------------------------------------------------------------
 
Predicate Information (identified by operation id):
---------------------------------------------------
 
  1 - access("A"."ID"="B"."ID")
  2 - filter("B"."ID"=40000)
  3 - filter("A"."ID"=40000)
 
Note
-----
  - dynamic sampling used for this statement
 
Statistics
----------------------------------------------------------
          9  recursive calls
          0  db block gets
      16151  consistent gets
      11469  physical reads
          0  redo size
        588  bytes sent via SQL*Net to client
        385  bytes received via SQL*Net from client
          2  SQL*Net roundtrips to/from client
          2  sorts (memory)
          0  sorts (disk)
          1  rows processed
熟悉执行计划的就可以看出,这个sql执行是很慢的,,2个表都做的是全表扫描,并且其物理读是11469,按照优化的经验,给2个表的id创建索引,减少查询时候的物理读,下面我们就看看通过优化器,oracle能我们什么样的建议呢?

linux

Related labels:
sql
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template