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Python的dict转object

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Release: 2016-06-07 16:31:03
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项目数据库是mongoDB,用pymongo进行find操作,查询结果是一串dict。现在要把查询结果用xlwt导出为csv文件,例如有一条数据如下: # dict数据row = { domain : dmyz.org, page_rank : 2, city : Beijing, country : China}# 以下是csv相关代码fields = ['dom

项目数据库是mongoDB,用pymongo进行find操作,查询结果是一串dict。现在要把查询结果用xlwt导出为csv文件,例如有一条数据如下:

# dict数据
row = {
    "domain" : "dmyz.org",
    "page_rank" : 2,
    "city" : "Beijing",
    "country" : "China"
}
# 以下是csv相关代码
fields = ['domain', 'page_rank', 'country', 'city']
wb = xlwt.Workbook()
ws = wb.add_sheet('Sheet1')
for i in range(len(fields)):
    ws.write(0, i, fields[i])
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要得到domain的值,是用row['domain'],但我希望能用对象的访问形式,例如row.domain来获取(严格来说这篇文章的标题有歧义,我真正的需求是改变dict的访问形式,而且Python中一切都是对象,object也是dict的基类。)

要实现这个需求,最容易想到的是用循环来做:

def _dict_to_object(d):
    class _O: pass
    [setattr(_O, _k, d[_k]) for _k in d]
    return _O
r = _dict_to_object(row)
print r.page_rank
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上面的代码就是定义一个名为_O的类,用setattr函数(或者__setattr__方法),把dict添加进去。

更简单的做法是利用类的__dict__方法:

class Struct:
    def __init__(self, **entries):
        self.__dict__.update(entries)
r = Struct(**row)
print row.page_rank
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以上例子中的dict只有一层,实际生产环境中,这个dict是两层的,所以实际的代码做了些改动:

row = {
    "url" : {
        "domain" : "dmyz.org"
    },
    "page_rank" : 2,
    "geography" : {
        "city" : "Beijing",
        "country" : "China"
    }
}
def _dict_to_object(d):
    class O: pass
    for _k in d:
        if type(d[_k]) == dict:
            setattr(O, _k, Struct(**d[_k]))
        else:
            setattr(O, _k, d[_k])
    return O
r = _dict_to_object(row)
print r.url.domain
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如果层次更多,就改成迭代的写法。还想到一个简单的思路:mongoDB的数据都是存成json的,只要在解析json时,替换dict的处理,也就是加上object_hook就可以实现了:

from collections import namedtuple
row = '''{
    "url" : {
        "domain" : "dmyz.org"
    },
    "page_rank" : 2,
    "geography" : {
        "city" : "Beijing",
        "country" : "China"
    }
}'''
x = json.loads(row, object_hook=lambda d: namedtuple('X', d.keys())(*d.values()))
print x.url.domain
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但这样要把pymongo查询出来的dict转成str再做处理,多了一步无用的操作,暂时没想到好的解决方案。

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