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怎样输出XML所有的同名节点内容?

WBOY
Release: 2016-06-06 20:18:36
Original
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现有的PHP代码输出XML节点时,只能输出第一个同名节点内容"100". 请问怎样才能输出所有节点的内容呢?

现有代码:
/* $xmlstring 原内容:


-
id*cn
100
101
102
103
105

*/

$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
foreach ($users as $user) {

<code>$html .= 'outputCustomer:'.get_txt($user,'Customer').'<br>';
$html .= 'outputGeo:'.get_txt($user,'GeocallCLI').'<br>';</code>
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Copy after login

}
echo $html;

function get_txt($parent, $name) {

<code>$nodes = $parent->getElementsByTagName($name);
return $nodes->item(0)->nodeValue;</code>
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Copy after login

}
?>

另问怎样只输出 idcn节点中号前面部份, 即 id 而不是 id*cn

回复内容:

现有的PHP代码输出XML节点时,只能输出第一个同名节点内容"100". 请问怎样才能输出所有节点的内容呢?

现有代码:
/* $xmlstring 原内容:


-
id*cn
100
101
102
103
105

*/

$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
foreach ($users as $user) {

<code>$html .= 'outputCustomer:'.get_txt($user,'Customer').'<br>';
$html .= 'outputGeo:'.get_txt($user,'GeocallCLI').'<br>';</code>
Copy after login
Copy after login

}
echo $html;

function get_txt($parent, $name) {

<code>$nodes = $parent->getElementsByTagName($name);
return $nodes->item(0)->nodeValue;</code>
Copy after login
Copy after login

}
?>

另问怎样只输出 idcn节点中号前面部份, 即 id 而不是 id*cn

自己顶上, 哪位大侠能解答下么
我顶

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