PHP计算某时间段内有几个周及某时间为今年第几周函数
date_default_timezone_set('PRC');
function count_weeks($startDate, $endDate = ''){
//开始时间
$startDate = date('Y-m-d', $startDate);
//结束时间
if(empty($endDate)) {
$endDate = date('Y-m-d');
}else{
$endDate = date('Y-m-d', $endDate);
}
//跨越天数
$n = (strtotime($endDate)-strtotime($startDate))/86400;
//判断，跨度小于7天，可能是同一周，也可能是两周
$endDate = date("Y-m-d",strtotime("$endDate +1 day"));
if($n<7){
//查开始时间 在 那周 的 位置
$day = date("w",strtotime($startDate))-1;
//查开始时间 那周 的 周一
$week_start = date("Y-m-d",strtotime("$startDate -{$day} day"));
//查开始时间 那周 的 周末
$day = 7-$day;
$week_end = date("Y-m-d",strtotime("$startDate +{$day} day"));
//判断周末时间是否大于时间段的结束时间，如果大于，那就是时间段在同一周，否则时间段跨两周
if($week_end>=$endDate){
$weekList[] =array('s'=>$startDate, 'e'=>date("Y-m-d",strtotime("$endDate -1 day")));
}else{
$weekList[] =array('s'=>$startDate, 'e'=>date("Y-m-d",strtotime("$week_end -1 day")));
$weekList[] =array('s'=>$week_end, 'e'=>date("Y-m-d",strtotime("$endDate -1 day")));
}
}else{
//如果跨度大于等于7天，可能是刚好1周或跨2周或跨N周，先找出开始时间 在 那周 的 位置和那周的周末时间
$day = date("w",strtotime($startDate))-1;
$week_start = date("Y-m-d",strtotime("$startDate -{$day} day"));
$day = 7-$day;
$week_end = date("Y-m-d",strtotime("$startDate +{$day} day"));
//先把开始时间那周写入数组
$weekList[] =array('s'=>$startDate, 'e'=>date("Y-m-d",strtotime("$week_end -1 day")));
//判断周末是否大于等于结束时间，不管大于(2周)还是等于(1周)，结束时间都是时间段的结束时间。
if($week_end >= $endDate){
$weekList[] = array('s'=>$week_end, 'e'=>date("Y-m-d",strtotime("$endDate -1 day")));
}else{
//N周的情况用while循环一下，然后写入数组
while($week_end <= $endDate){
$start = $week_end;
$week_end = date("Y-m-d",strtotime("$week_end +7 day"));
if($week_end <= $endDate){
$weekList[] = array('s'=>$start, 'e'=>date("Y-m-d",strtotime("$week_end -1 day")));
}else{
$weekList[] = array('s'=>$start, 'e'=>date("Y-m-d",strtotime("$endDate -1 day")));
}
}
}
}
return $weekList;
}PHP获取某时间为今年第几周方法
date('W')
