PHP int 超大溢出整数的 加减运算函数，如果有更好的方法欢迎探讨

<br />
一代码太多；<br />
二只有加减运算，乘除取余都没有；<br />

<br />
mysql> SELECT 11234123413241341234123412341234+1;<br />
+------------------------------------+<br />
| 11234123413241341234123412341234+1 |<br />
+------------------------------------+<br />
|   11234123413241341234123412341235 |<br />
+------------------------------------+<br />
1 row in set (0.00 sec)<br />
<br />
<br />
mysql> SELECT 11234123413241341234123412341234*12341234123;<br />
+----------------------------------------------+<br />
| 11234123413241341234123412341234*12341234123 |<br />
+----------------------------------------------+<br />
|   138642947209487270472850788378836360727782 |<br />
+----------------------------------------------+<br />
1 row in set (0.00 sec)<br />
<br />
<br />

<br>
/* big int operate [by fuzb 20130826] */<br>
function bigintO($num1,$op,$num2)<br>
{<br>
    $arr = array();<br>
    $endop = '';<br>
    $num1o = $num1;<br>
    $num2o = $num2;<br>
    if($num1 
    {<br>
        $c1 = -1;<br>
        $num1 = preg_replace('/^(-)/','',$num1);<br>
<br>
    } else {<br>
        $c1 = 1;<br>
    }<br>
<br>
    if($num2 
    {<br>
        $c2 = -1;<br>
        $num2 = preg_replace('/^(-)/','',$num2);<br>
    } else {<br>
        $c2 = 1;<br>
    }<br>
<br>
    $len1 = strlen($num1);<br>
    $len2 = strlen($num2);<br>
    $len = max(strlen($num1),strlen($num2));<br>
    if($len1 
    if($len2 
<br>
<br>
    if($op == '+')<br>
    {<br>
        if($c1 == $c2)<br>
        { <div class="clear">
                 
              
              
        
            </div>