我正在尝试以不涉及任何页面刷新的方式重写我的表单。换句话说，我不希望浏览器在提交时发出任何 GET/POST 请求。 jQuery 应该可以帮我解决这个问题。 这是我的表格（我有一些）：

    <!-- I guess this action doesn't make much sense anymore -->
    <form action="/save-user" th:object="${user}" method="post">
         <input type="hidden" name="id" th:value="${user.id}">
    
         <input type="hidden" name="username"
              th:value="${user.username}">
    
         <input type="hidden" name="password"
              th:value="${user.password}">
    
         <input type="hidden" name="name" th:value="${user.name}">
    
         <input type="hidden" name="lastName"
              th:value="${user.lastName}">
    
         <div class="form-group">
              <label for="departments">Department: </label>
              <select id="departments" class="form-control"
                       name="department">
                  <option th:selected="${user.department == 'accounting'}"
                          th:value="accounting">Accounting
                  </option>
                  <option th:selected="${user.department == 'sales'}"
                          th:value="sales">Sales
                  </option>
                  <option th:selected="${user.department == 'information technology'}"
                          th:value="'information technology'">IT
                  </option>
                  <option th:selected="${user.department == 'human resources'}"
                          th:value="'human resources'">HR
                  </option>
                  <option th:selected="${user.department == 'board of directors'}"
                          th:value="'board of directors'">Board
                  </option>
              </select>
          </div>
    
          <div class="form-group">
              <label for="salary">Salary: </label>
              <input id="salary" class="form-control" name="salary"
                     th:value="${user.salary}"
                     min="100000" aria-describedby="au-salary-help-block"
                     required/>
              <small id="au-salary-help-block"
                     class="form-text text-muted">100,000+
              </small>
          </div>
    
          <input type="hidden" name="age" th:value="${user.age}">
    
          <input type="hidden" name="email" th:value="${user.email}">
    
          <input type="hidden" name="enabledByte"
                 th:value="${user.enabledByte}">
          
          <!-- I guess I should JSON it somehow instead of turning into regular strings -->
          <input type="hidden" th:name="authorities"
                 th:value="${#strings.toString(user.authorities)}"/>
    
          <input class="btn btn-primary d-flex ml-auto" type="submit"
                 value="Submit">
      </form>

这是我的 JS：

$(document).ready(function () {
    $('form').on('submit', async function (event) {
        event.preventDefault();

        let user = {
            id: $('input[name=id]').val(),
            username: $('input[name=username]').val(),
            password: $('input[name=password]').val(),
            name: $('input[name=name]').val(),
            lastName: $('input[name=lastName]').val(),
            department: $('input[name=department]').val(),
            salary: $('input[name=salary]').val(),
            age: $('input[name=age]').val(),
            email: $('input[name=email]').val(),
            enabledByte: $('input[name=enabledByte]').val(),
            authorities: $('input[name=authorities]').val()

            /*
            ↑ i tried replacing it with authorities: JSON.stringify($('input[name=authorities]').val()), same result
            */
        };

        await fetch(`/users`, {
            method: 'PUT',
            headers: {
                ...getCsrfHeaders(),
                'Content-Type': 'application/json',
            },
            body: JSON.stringify(user) // tried body : user too
        });

    });
});

function getCsrfHeaders() {
    let csrfToken = $('meta[name="_csrf"]').attr('content');
    let csrfHeaderName = $('meta[name="_csrf_header"]').attr('content');

    let headers = {};
    headers[csrfHeaderName] = csrfToken;
    return headers;
}

这是我的 REST 控制器处理程序：

    // maybe I'll make it void. i'm not sure i actually want it to return anything
    @PutMapping("/users")
    public User updateEmployee(@RequestBody User user) {
        service.save(user); // it's JPARepository's regular save()
        return user;
    }

User 实体：

@Entity
@Table(name = "users")
@Data
@EqualsAndHashCode
public class User implements UserDetails {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column
    private long id;
    @Column(nullable = false, unique = true)
    private String username;
    @Column(nullable = false)
    private String password;
    @Column
    private String name;
    @Column(name = "last_name")
    private String lastName;
    @Column
    private String department;
    @Column
    private int salary;
    @Column
    private byte age;
    @Column
    private String email;
    @Column(name = "enabled")
    private byte enabledByte;
    @ManyToMany
    @JoinTable(name = "user_role",
            joinColumns = {@JoinColumn(name = "user_id", referencedColumnName = "id"),
                    @JoinColumn(name = "username", referencedColumnName = "username")},
            inverseJoinColumns = {@JoinColumn(name = "role_id", referencedColumnName = "id"),
                    @JoinColumn(name = "role", referencedColumnName = "role")})
    @EqualsAndHashCode.Exclude
    private Set<Role> authorities;

角色实体：

@Entity
@Table(name = "roles")
@Data
@EqualsAndHashCode
public class Role implements GrantedAuthority {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column
    private long id;
    @Column(name = "role", nullable = false, unique = true)
    private String authority;
    @ManyToMany(mappedBy = "authorities")
    @EqualsAndHashCode.Exclude
    private Set<User> userList;

当我按下提交按钮时，我会在控制台中看到此内容

WARN 18252 --- [io-8080-exec-10] .w.s.m.s.DefaultHandlerExceptionResolver : Resolved [org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot deserialize value of type `java.util.HashSet<pp.spring_bootstrap.models.Role>` from String value (token `JsonToken.VALUE_STRING`)]

看来我应该以某种方式传递 Collection 的 JSON 表示，而不仅仅是 String。在我之前的项目中，没有使用 jQuery，String 已使用我的自定义 Formatter 成功反序列化

@Override
    public void addFormatters(FormatterRegistry registry) {
        registry.addFormatter(new Formatter<Set<Role>>() {
            @Override
            public Set<Role> parse(String text, Locale locale) {
                Set<Role> roleSet = new HashSet<>();
                String[] roles = text.split("^\[|]$|(?<=]),\s?");
                for (String roleString : roles) {
                    if (roleString.length() == 0) continue;
                    String authority =
                            roleString.substring(roleString.lastIndexOf("=") + 2,
                                    roleString.indexOf("]") - 1);
                    roleSet.add(service.getRoleByName(authority));
                }
                return roleSet;
            }

            @Override
            public String print(Set<Role> object, Locale locale) {
                return null;
            }
        });
    }

我用谷歌搜索了一下，看来 Thymeleaf 没有任何 toJson() 方法。我的意思是我可以编写自己的方法，但我不知道如何在 Thymeleaf 模板中使用它们。此外，这可能不是最优的解决方案

这是一个 Boot 项目，所以我有 Jackson 数据绑定库

如何正确地将 Collection 从我的表单传递到 JS 事件处理程序，然后传递到 REST 控制器？

我检查了 StackOverflow 建议的多个类似问题。它们看起来不相关（例如，它们涉及不同的编程语言，例如 C# 或 PHP）

UPD：我刚刚尝试过这个。可惜也没有发挥作用！ （错误信息相同）

// inside my config
    @Bean
    public Function<Set<Role>, String> jsonify() {
        return s -> {
            StringJoiner sj = new StringJoiner(", ", "{", "}");
            for (Role role : s) {
                sj.add(String.format("{ \"id\" : %d, \"authority\" : \"%s\" }", role.getId(), role.getAuthority()));
            }
            return sj.toString();
        };
    }

    <input type="hidden" th:name="authorities" 
           th:value="${@jsonify.apply(user.authorities)}"/>

不过，该方法按预期工作

$(document).ready(function () {
    $('form').on('submit', async function (event) {
        /*
        ↓ logs:
          authorities input: {{ "id" : 1, "authority" : "USER" }}
        */
        console.log('authorities input: ' + 
                   $('input[name=authorities]').val());

UPD2：GPT4 建议这样做

authorities: JSON.parse($('input[name=authorities]').val())

现在真的很奇怪。数据库仍然没有改变，但是！ IDE 控制台现在没有错误，也根本没有提及 PUT 请求（之前的尝试中也有）！此外，浏览器日志有此消息

Uncaught (in promise) SyntaxError: Expected property name or '}' in JSON at position 1
    at JSON.parse (<anonymous>)
    at HTMLFormElement.<anonymous> (script.js:28:31)
    at HTMLFormElement.dispatch (jquery.slim.min.js:2:43114)
    at v.handle (jquery.slim.min.js:2:41098)

不知道什么意思！

UPD3：GPT4 很智能。反正比我聪明。这是绝对正确的。它在 UPD2 中不起作用的原因是我忽略了它所说的另一件事：

权限字段应作为对象的数组而不是字符串发送。

这意味着我应该使用方括号，而不是大括号，作为我的 StringJoiner 前缀和后缀：

    // I also added some line breaks, but I doubt it was necessary
    @Bean
    public Function<Set<Role>, String> jsonify() {
        return s -> {
            StringJoiner sj = new StringJoiner(",\n", "[\n", "\n]");
            for (Role role : s) {
                sj.add(String.format("{\n\"id\" : %d,\n\"authority\" : \"%s\"\n}", role.getId(), role.getAuthority()));
            }
            return sj.toString();
        };
    }

我也改了，比如这个

username: $('input[name=username]').val()

对此（我没有立即这样做真是愚蠢）

username: $(this).find('input[name=username]').val()

并且 - 中提琴 - 现在可以使用了！

GPT4 也注意到我使用了

'input[name=department]'

而不是

'select[name=department]'

我也解决了这个问题