使用C++編寫的陣列右旋轉的反轉演算法

Input : arr[ ] = { 4, 6, 2, 6, 43, 7, 3, 7 }, k = 4
Output : { 43, 7, 3, 7, 4, 6, 2, 6 }
Explanation : Rotating each element of array by 4-element to the right gives { 43, 7, 3, 7, 4, 6, 2, 6 }.

Input : arr[ ] = { 8, 5, 8, 2, 1, 4, 9, 3 }, k = 3
Output : { 4, 9, 3, 8, 5, 8, 2, 1 }

using namespace std;
#include <bits/stdc++.h>

void reverse(int nums[], int start,int end) {
   int temp=0;
   // reversing array with swapping start element with end element.
   while(start<=end){
      temp=nums[end];
      nums[end]=nums[start];
      nums[start]=temp;
      start++;
      end--;
   }
}

int main() {
   int arr[] = {4, 6, 2, 6, 43, 7, 3, 6, 2, 4, 5 };

   int N = sizeof(arr)/sizeof(arr[0]);

   int k = 4;
   // reversing whole array
   reverse(arr, 0, N-1);
   k = k%N;
   // reversing element range of 0 to k-1.

   reverse(arr, 0, k-1);
   // reversing element range of k to last element.
   reverse(arr, k, N-1);
   cout << "Array after rotating by k-elements : ";
   for(int i = 0;i<N;i++)
      cout << arr[i] << " ";
   return 0;
}

Array after rotating by k-elements : 6 2 4 5 4 6 2 6 43 7 3