在本文中，我們將討論如何從一個只包含0和1字元的給定字串中刪除兩個零之間的元素。最終的字串不應包含任何被0包圍的字元'1'。例如-
Input : string = “110010” Output : “11000” Explanation: 1 is found between two zeros at the 4th index. Input : string = “0010” Output : “000” Explanation : 1 is found between two zeros at the 2nd index.
We can apply a simple approach, i.e., traverse the string using a loop and check the previous and next elements whether they are zeros; if yes, previous and next elements whether they are zeros; if yes, previous and next elements whether they are zeros; if yes, previous and next elements whether they are zeros; if yes, previous and next elements whether they are zeros; if yes, previous and next elements whether they are zeros; if yes, previous and next elements whether they are zeros; if yes, previous and next elements whether they are zeros； then that index is not zero. After that, update the variable with a new length that stores length and print that string.
#include <bits/stdc++.h>
using namespace std;
int main () {
string str = "110010";
int length = str.length();
for (int i = 1; i < length - 1; i++) {
// checking the element between two zeros
if ((str.at (i - 1) == '0' && str.at (i + 1) == '0')) {
// deleting the element
// if it is found between two 0's
str.erase (i, 1);
i--;
if (i > 0 && str.at (i - 1) == '0')
i--;
// updating the length of the string after removing the element.
length = str.length ();
}
}
cout << "String after removing elements between the two zeros: " << str;
return 0;
}String after removing elements between the two zeros: 1100
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