redis localhost:6379> sadd userlist 1 (integer) 1 redis localhost:6379> sadd userlist 2 (integer) 1 redis localhost:6379> sadd userlist 3 (integer) 1 redis localhost:6379> sadd userlist 4 (integer) 1 redis localhost:6379> sadd userlist 5 (integer) 1 redis localhost:6379> set score:user:1 20 OK redis localhost:6379> set score:user:2 15 OK redis localhost:6379> set score:user:3 11 OK redis localhost:6379> set score:user:4 24 OK redis localhost:6379> set score:user:5 15 OK redis localhost:6379> set age:user:1 29 OK redis localhost:6379> set age:user:2 35 OK redis localhost:6379> set age:user:3 25 OK redis localhost:6379> set age:user:4 31 OK redis localhost:6379> set age:user:5 27 OK
如上redis结构，如何实现sort的时候根据score倒排序，如果score相等（上面user2和user5的score相等），那么按照age正排序？
期望最后得到的userid排序结果为:
4 1 5 2 3
请问各位：这样的命令该如何写，或者有没有比较好的解决方案
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You can consider sorted set. Set is just a collection and itself is unsorted, while sorted set supports sorting according to score
sort userlist by score:user:* desc
Maintain two zsets
Sort by age: zadd sort_user_age username age
Sort by score: zadd sort_user_score username score
Then save the user's information in string format, sort it in a certain way and then go to mget.
If you want to sort, you must use zadd, but what you said is more complicated, so you need to think about it