Stuck on the step of grouping char[] and then converting it to int

Do it directly like this, convert every 5 to an int, sample code (may have BUG):

        char[] chArr = {0,0,0,0,1,1,1,0,0,1};
        for (int i = 0; i < chArr.length; i+=5) {
            // 直接组装为int
            int result = 0;
            for (int j = 0; j < 5; j++) {
                result += (int) chArr[i+j] * MathUtil.pow(2, 4-j);
            }
            System.out.println(result);
        }

    /* MathUtil.java */
    /**
     * 整数的几次方
     * @param baseNumber 底数
     * @param exponent 指数
     * @return 计算出的值
     */
    public static int pow(int baseNumber, int exponent) {
        if (exponent < 0) {
            throw new IllegalArgumentException("exponent cant not be a negative number");
        }
        if (exponent == 0) {
            return 1;
        }
        return baseNumber << (exponent - 1); 
    }