尝试抓取instagram图片分享地址从而下载图片
# -*- coding: utf-8 -*-
import urllib2
import re
response = urllib2.urlopen('https://www.instagram.com/p/BG5SpsYuSr-/')
html = response.read()
#print html
catch = re.compile(r'//*[display_src="(.+?\.jpg)"]')
urls = re.findall(catch,html)
for i, url in enumerate(urls):
print url
查看源代码发现图片地址在这两个地方
想请教一下各位怎样抓取图片的下载地址？
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
As you can see from the second picture, the image address is in the js object. According to experience, the image is probably added by js. I can't enter the target website, so I don't know what it looks like.
You can try to use this regular expression to extract the js object, convert it into json, and then get the data you want just like operating a dictionary