类型转换 - 如何将C++ string 类型的每一位字符转换成int（并不是将整个string转换成int）？

Question

string str ="123456";如何把str的每一位str[i]转换成数字？ 已经尝试：用int(str[i])只能得到ascii码。用atoi(str.c_str())也只能将整个string转换成int。

怪我咯 · Answer

You have already got the ASCII code, isn’t it just a number after subtracting ‘0’ (that is, 48)...

迷茫 · Answer

#include 
#include 

using namespace std;


int main(){
    string str = "123456";
    const char *p = str.c_str();
    for (int i = 0; i < str.length(); i++)
    {
        int a = str[i] - '0';
        printf("%d 
", a);

    }
    system("pause");
    return 0;
}