C++中指针赋值后 exe程序无法运行

Question

我在Win8中 使用codeblock编写了一段程序。使用的是GCC 4.7 &amp; 4.8 编译器： {代码...} 程序可以运行，输出：Hello world。很奇怪的是一旦加入指针赋值语句，编译组建通过，但无法运行。 {代码...} 控制台上显...

大家讲道理 · Answer

int *i = 0；

This statement is equivalent to assigning the pointer variable i of int* to 0, instead of pointing the pointer i of int* to the memory address where the constant 0 is located, which is equivalent to the following code:

int *i;
i=0;

instead of

int *i;
*i= 0;    //不过这样的用法也不规范！这句代码的作用是为指针 i所指向的内存赋值，
          //但是因为i 指向未知内存，因为前面只是进行了初始化，所以这时候是一个野指针
          //为野指针指向的内存赋值，显然会导致内存错误！

Is this what you understand? @changqngd

阿神 · Answer

I just ran it a few times and thought about it, and finally figured it out.
The error is:
int *i=0; //这里给指针赋了一个空地址 *i = 9; //*i is a null address pointer and cannot be used
It is correct to change it to the following:

int ival=90;
int *i = &ival；
*i=9;