个人觉得echarts的折线图就能实现啊：http://echarts.baidu.com/demo...

http://echarts.baidu.com/

做出来了，虽然不是很完善，各位大神指导
function fun(id){
    return document.getElementById(id);
}
var timer=null;
//var i = -10;
//var j=1;
    //画方格
    function drawGrid(){
            var c_canvas = document.getElementById("ecgBc");
            drawSmallGrid(c_canvas);
            drawMediumGrid(c_canvas);
            drawBigGrid(c_canvas);
            return;
        }
    function drawSmallGrid(c_canvas){
        var context = c_canvas.getContext("2d");
        context.strokeStyle = "#f1dedf";
        context.strokeWidth=1;
        context.beginPath();
        for (var x = 0.5; x < 1500; x += 3) {
            context.moveTo(x, 0);
            context.lineTo(x, 1500);
            context.stroke();
        }
        for (var y = 0.5; y < 1500; y += 3) {
            context.moveTo(0, y);
            context.lineTo(1500, y);
            context.stroke();
        }
        context.closePath();
        return;
    }
    function drawMediumGrid(c_canvas){
        var context = c_canvas.getContext("2d");
        context.strokeStyle = "#f0adaa";
        context.strokeWidth=1;
        context.beginPath();
        for (var x = 0.5; x < 1500; x += 15) {
            context.moveTo(x, 0);
            context.lineTo(x, 1500);
            context.stroke();
        };
        for (var y = 0.5; y < 1500; y += 15) {
            context.moveTo(0, y);
            context.lineTo(1500, y);

            context.stroke();
        };
        context.closePath();
        return;
    }
    function drawBigGrid(c_canvas){
        var context = c_canvas.getContext("2d");
        context.strokeStyle = "#e0514b";
        context.strokeWidth=1;
        context.beginPath();
        for (var x = 0.5; x < 1500; x += 75) {
            context.moveTo(x, 0);
            context.lineTo(x, 1500);
            context.stroke();
        };
        for (var y = 0.5; y < 1500; y += 75) {
            context.moveTo(0, y);
            context.lineTo(1500, y);
            context.stroke();
        };
        context.closePath();
        return;
    }
    drawGrid();

    //画曲线
        $.ajax({
            url : "../data/test.json",
            success : function(data) {
                fillDatas(data.wave_data);
                //fillDatasMiro(data.wave_data);
            }
        });
    function fillDatas(short_array) {
        var canvasline = document.getElementById("ecg");
       var linectx = canvasline.getContext("2d");
        var totalPointCount = short_array.length;
            var pointX = 0;
            var pointY = 0;
             linectx.beginPath();
        //setInterval(function () {
        //    linectx.clearRect(0,0,1500,1000);
        //    linectx.save();
        //    i--;
            linectx.scale(1,0.5);
        linectx.translate(0,750);
            for (var point_index = 0; point_index < totalPointCount; ++point_index) {
                i--;
                //setTimeout(linectx.translate(i,750),2000);
                pointX +=point_index/10;
                pointY = short_array[point_index];
                linectx.lineTo(pointX,pointY);
            }
            linectx.stroke();
            //linectx.restore();
        //},2000);
        return;
    }
//var canvasline = document.getElementById("ecg");
//var linectx = canvasline.getContext("2d");
//setInterval(function () {
//    linectx.clearRect(0,0,1500,1000);
//    linectx.save();
//    j++;
//    linectx.translate(j,0);
//    dra();
//    linectx.restore();
//},50);
//function dra(){
//    linectx.fillRect(0,0,100,100);
//}



    //function fillDatasMiro(short_array) {
    //    var canvasline = document.getElementById("ecgMiro");
    //    var linectx = canvasline.getContext("2d");
    //    var totalPointCount = short_array.length;
    //    var pointX = 0;
    //    var pointY = 0;
    //    linectx.beginPath();
    //    linectx.scale(1,0.5);
    //    linectx.translate(0,1500);
    //    for (var point_index = 0; point_index < totalPointCount; ++point_index) {
    //        pointX +=point_index/10*2;
    //        pointY = short_array[point_index]*2;
    //        linectx.lineTo(pointX,pointY);
    //    }
    //    linectx.stroke();
    //    linectx.closePath();
    //    return;
    //};


//fun('ecgLine').onmousemove=function (e){
//        //放大镜特效
//        //alert(1);
//        var e=e||event;
//        fun('moro').style.display="block";
//        fun('moro').scrollLeft= e.offsetX*2-180;
//        fun('moro').scrollTop= e.offsetY*2-130;
//            //跟随特效
//        fun('moro').style.left= e.pageX+20+'px';
//        fun('moro').style.top= e.pageY+20+'px';
//        };
//    fun('ecgLine').onmouseout=function () {
//        fun('moro').style.display="none";
//        };