想做一个ajax局部刷新分页跳转,可是不知道为什么用ajax接受的数据在页面
上显示出来总是这么一句话MySql ErrorNo database selected 然后我做了几个测试
发现echo"111111";echo"22222";echo"3333"echo"4444";只有4444输出!PHP我不是很懂
所以想麻烦大神们看下是怎么回事!小弟在此谢过了!
<meta http-equiv="Content-Type" content="text/html; charset=utf8" />
<?php
if($_REQUEST['page'])
{
$page = $_REQUEST['page'];
$page=1;
$cur_page = $page;
$page -= 1;
$per_page = 10;
$previous_btn = true;
$next_btn = true;
$first_btn = true;
$last_btn = true;
$start = $page * $per_page;
$conn=mysqli_connect("localhost","root","","info");
mysqli_query($conn,"SET NAMES 'utf8'");
**echo "44444444";**
$query_pag_data = "SELECT id,name from content LIMIT $start, $per_page";
$result_pag_data = mysql_query($query_pag_data) or die('MySql Error' . mysql_error());
$msg = "";
while ($row = mysql_fetch_array($result_pag_data)) {
$htmlmsg=htmlspecialchars($row['name']);
$msg .= "<li><b>" . $row['id'] . "</b> " . $htmlmsg . "</li>";
}
$msg = "<p class='data'><ul>" . $msg . "</ul></p>"; // Content for Data
**echo "3333333333333333333333";**
/* --------------------------------------------- */
$query_pag_num = "SELECT COUNT(*) AS count FROM content";
$result_pag_num = mysql_query($query_pag_num);
$row = mysql_fetch_array($result_pag_num);
$count = $row['count'];
$no_of_paginations = ceil($count / $per_page);
**echo "2222222222";**
/* ---------------Calculating the starting and endign values for the loop----------------------------------- */
if ($cur_page >= 7) {
$start_loop = $cur_page - 3;
if ($no_of_paginations > $cur_page + 3)
$end_loop = $cur_page + 3;
else if ($cur_page <= $no_of_paginations && $cur_page > $no_of_paginations - 6) {
$start_loop = $no_of_paginations - 6;
$end_loop = $no_of_paginations;
} else {
$end_loop = $no_of_paginations;
}
} else {
$start_loop = 1;
if ($no_of_paginations > 7)
$end_loop = 7;
else
$end_loop = $no_of_paginations;
}
/* ----------------------------------------------------------------------------------------------------------- */
$msg .= "<p class='pagination'><ul>";
// FOR ENABLING THE FIRST BUTTON
if ($first_btn && $cur_page > 1) {
$msg .= "<li p='1' class='active'>First</li>";
} else if ($first_btn) {
$msg .= "<li p='1' class='inactive'>First</li>";
}
// FOR ENABLING THE PREVIOUS BUTTON
if ($previous_btn && $cur_page > 1) {
$pre = $cur_page - 1;
$msg .= "<li p='$pre' class='active'>Previous</li>";
} else if ($previous_btn) {
$msg .= "<li class='inactive'>Previous</li>";
}
for ($i = $start_loop; $i <= $end_loop; $i++) {
if ($cur_page == $i)
$msg .= "<li p='$i' style='color:#fff;background-color:#006699;' class='active'>{$i}</li>";
else
$msg .= "<li p='$i' class='active'>{$i}</li>";
}
// TO ENABLE THE NEXT BUTTON
if ($next_btn && $cur_page < $no_of_paginations) {
$nex = $cur_page + 1;
$msg .= "<li p='$nex' class='active'>Next</li>";
} else if ($next_btn) {
$msg .= "<li class='inactive'>Next</li>";
}
// TO ENABLE THE END BUTTON
if ($last_btn && $cur_page < $no_of_paginations) {
$msg .= "<li p='$no_of_paginations' class='active'>Last</li>";
} else if ($last_btn) {
$msg .= "<li p='$no_of_paginations' class='inactive'>Last</li>";
}
$goto = "<input type='text' class='goto' size='1' style='margin-top:-1px;margin-left:60px;'/><input type='button' id='go_btn' class='go_button' value='Go'/>";
$total_string = "<span class='total' a='$no_of_paginations'>Page <b>" . $cur_page . "</b> of <b>$no_of_paginations</b></span>";
$msg = $msg . "</ul>" . $goto . $total_string . "</p>"; // Content for pagination
**echo $msg;**
**echo "1111111111111";**
}
?>
看一下文档啊 少年 点击链接
既然你是用的mysqli,三楼说的没错,选择一下数据库,mysqli是
mysqli_select_db()
这个,链接里有,你看下。mysql 和mysqli混用!
上面用的
$conn=mysqli_connect("localhost","root","","info");
下面用
mysql_query($query_pag_data)
要不改成
这个报错是因为没有选择数据库呀,你在连接之后执行一下
mysqli_query('use database')
,database
是你的数据库,另外像楼上说的,别mysqli和mysql混杂用,php官方已经放弃mysql
扩展了,用pdo
或者mysqli