Retrieve next/previous record from MySQL query sorted by multiple columns
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P粉006977956 2024-03-22 11:08:54
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I'm running the query through my MySQL database (MariaDB 10.3) like this:

SELECT * FROM my_table ORDER BY priority DESC, expiration_date ASC, id ASC

An example of this table with the given order looks like this:

id ... priority expiration_date
3 ... 2 2022-07-01 12:00:00
7 ... 2 2022-07-03 12:00:00
6 ... 2 2022-07-04 12:00:00
9 ... 1 2022-07-02 12:00:00
4 ... 1 2022-07-05 12:00:00
11 ... 1 2022-07-05 12:00:00

Now I have the ID of a specific record and I am trying to retrieve the records that are before/after said record in the query result in the given order via SQL. Suppose I have record ID 6 and I want to return the records with ID 9 and 7 respectively.

Sort by a single unique column, which is easy to get in a single query, but I'm not sure how to handle multiple non-unique columns. Can someone tell me how to achieve this?

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reply all(1)
P粉763748806

Following Paul Maxwell's tips about LEAD and LAG, I was able to write a working query like this:

SELECT t.next_id 
FROM (
    SELECT id, 
        LEAD(id, 1) OVER (ORDER BY priority DESC, expiration_date ASC, id ASC) AS next_id 
    FROM my_table
) t 
WHERE t.id = ?

Retrieve previous records corresponding to LAG.

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