Implicit conversion from float (number) to int loses precision

Question

I used this formula before php8.1 <?php$number=0;echolog10(abs($number))/3|0;echoPHP_EOL;$number=100;echolog10(abs($number))/3| 0;echoPHP_EOL;$number=1100;echolog10(abs($number))/3|0;echoPHP_EOL;$number=10000000;e

P粉043295337 · Answer

// Implicit variant
$number= "2";
$calc = 2 + $number;

// Cast variant
$number = "2";
$calc= 2 + (int) $number;

// Explicit variant
$number = "2";
$calc = 2 + intval($number);

// Everything is good variant ^^
$number = 2;
$calc = 2 + $number;

P粉211600174 · Answer

When you perform a bitwise OR operation via the | operator, you get an implicit conversion to an integer. This is a...weird...way to convert to an integer. To avoid the warning, just cast explicitly.

Implicit:

echo log10(abs($number)) / 3 | 0;

Explicitly pass the function:

echo intval(log10(abs($number)) / 3);

Or via cast:

echo (int) (log10(abs($number)) / 3);