No qualified bean of type 'com.jpa.test.UserRepository' found exception occurred in the main thread
P粉170438285
P粉170438285 2023-08-29 14:35:44
0
1
406
<p>I am a beginner in Spring-boot and I faced this issue when I tried to run a Spring-boot application. </p> <pre class="brush:php;toolbar:false;">Exception in thread "main" org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type com. JPA. test. User Repository available at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBean(DefaultListableBeanFactory.java:340) at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBean(DefaultListableBeanFactory.java:331) at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:1148) at com. JPA. test. Test Application. main(TestApplication.java:17)</pre> <p>I want the data to be saved correctly in the database.</p> <p>Directory and folder arrangement: Directory and folder arrangement</p> <p>Error page: Error page 1 Error page 2</p> <p>Attribute interface: Attribute application page</p> <p>Main class code:</p> <pre class="brush:php;toolbar:false;">package com.jpa.test; import org.springframework.boot.SpringApplication; import org.springframework.boot.autoconfigure.SpringBootApplication; import org.springframework.boot.autoconfigure.jdbc.DataSourceAutoConfiguration; import org.springframework.context.ApplicationContext; @SpringBootApplication(exclude={DataSourceAutoConfiguration.class}) public class TestApplication { public static void main(String[] args) { ApplicationContext context = SpringApplication.run(TestApplication.class, args); UserRepository ur = context.getBean(UserRepository.class); User user = new User(); user.setName("XYZ"); user.setStatus("Active"); user.setCity("OOPS"); User save = ur.save(user); System.out.println(save); } }</pre> <p>Entity class (user):</p> <pre class="brush:php;toolbar:false;">package com.jpa.test; import jakarta.persistence.Entity; import jakarta.persistence.GeneratedValue; import jakarta.persistence.GenerationType; import jakarta.persistence.Id; @Entity public class User { @Id @GeneratedValue(strategy = GenerationType.AUTO) private int id; private String name; private String city; private String status; public User() { super(); // TODO Auto-generated constructor stub } public User(int id, String name, String city, String status) { super(); this.id = id; this.name = name; this.city = city; this.status = status; } public int getId() { return id; } public void setId(int id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } public String getCity() { return city; } public void setCity(String city) { this.city = city; } public String getStatus() { return status; } public void setStatus(String status) { this.status = status; } @Override public String toString() { return "User [id=" id ", name=" name ", city=" city ", status=" status "]"; } }</pre> <p>Dao(用户存储库)</p> <pre class="brush:php;toolbar:false;">package com.jpa.test; import org.springframework.data.repository.CrudRepository; import org.springframework.stereotype.Repository; @Repository public interface UserRepository extends CrudRepository<User, Integer> { }</pre></p>
P粉170438285
P粉170438285

reply all(1)
P粉345302753

Try adding these comments to your program:

@Configuration
@EnableAutoConfiguration
@ComponentScan
@EntityScan("com.jpa.test")
@EnableJpaRepositories("com.jpa.test")
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!