How to call PHP function through JavaScript?
P粉133321839
2023-07-30 18:57:00
<p>I'm trying to call a PHP function from an external PHP file into a JavaScript script. My code is more complex, so I'm writing a sample code here. </p><p>This is my PHP code: </p>
<pre class="lang-php prettyprint-override"><code><?php
function add($a,$b){
$c=$a $b;
return $c;
}
function mult($a,$b){
$c=$a*$b;
return $c;
}
function divide($a,$b){
$c=$a/$b;
return $c;
}
?>
</code></pre>
<p>JS code:</p>
<pre class="brush:php;toolbar:false;"><script>
var phpadd= add(1,2); //call the php add function
var phpmult= mult(1,2); //call the php mult function
var phpdivide= divide(1,2); //call the php divide function
</script></pre>
<p>This is what I want to do. </p><p>My original PHP file did not contain these math functions, but the idea is the same. </p><p>If there is no suitable solution, can you please provide an alternative, but it should call the value from an external PHP file. </p><p><strong></strong></p>
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Try this
Yes, you can send an Ajax request with data to the server using request parameters, like this (very simple):
Please note that the following code uses jQuery.
jQuery.ajax({ type: "POST", url: 'your_functions_address.php', dataType: 'json', data: {functionname: 'add', arguments: [1, 2]}, success: function (obj, textstatus) { if( !('error' in obj) ) { yourVariable = obj.result; } else { console.log(obj.error); } } });Your _functions_address.php file should look like this:
<?php header('Content-Type: application/json'); $aResult = array(); if( !isset($_POST['functionname']) ) { $aResult['error'] = 'No function name!'; } if( !isset($_POST['arguments']) ) { $aResult['error'] = 'No function arguments!'; } if( !isset($aResult['error']) ) { switch($_POST['functionname']) { case 'add': if( !is_array($_POST['arguments']) || (count($_POST['arguments']) < 2) ) { $aResult['error'] = 'Error in arguments!'; } else { $aResult['result'] = add(floatval($_POST['arguments'][0]), floatval($_POST['arguments'][1])); } break; default: $aResult['error'] = 'Not found function '.$_POST['functionname'].'!'; break; } } echo json_encode($aResult); ?>