#生成预处理对象
$sql = 'SELECT * FROM dede_archives WhERE id IN (:id)' ;
$stmt = $pdo -> prepare($sql);
#参数的绑定并执行
$id = implode(',',[2,3,4,5,6,7,8,9]);
#$stmt -> bindParam(':id',$id,PDO::PARAM_STR);
$stmt -> bindValue(':id','2,3,4,5,6,7,8,9',PDO::PARAM_STR);
$stmt -> execute();
结果只能查询到id为2的数据，其他id的数据查询不到！
在传递这些多个值的时候或者多条件的时候应该怎样写；
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
Just splice sql statements
TP5.1.21 After version, array query support:
To achieve this subquery:
1. First quote: use think\db\Where;
2. Define the array: $where = new Where;
3. You can use it: $where['title'] = ['like', "%".$sotitle."%"];
Reference address: https://blog.csdn.net/haibo0668/article/details/78295485