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Python获取HTTP请求的状态码(200,404等)

Python获取HTTP请求的状态码(200,404等),不访问整个页面源码,那样太浪费资源:

输入:segmentfault.com 输出:200
输入:segmentfault.com/nonexistant 输出:404

  • ringa_lee
  • ringa_lee    2017-06-28 09:27:312楼

    参考文章:Python实用脚本清单

    http不只有get方法(请求头部+正文),还有head方法,只请求头部

    import httplib
    
    def get_status_code(host, path="/"):
        """ This function retreives the status code of a website by requesting
            HEAD data from the host. This means that it only requests the headers.
            If the host cannot be reached or something else goes wrong, it returns
            None instead.
        """
        try:
            conn = httplib.HTTPConnection(host)
            conn.request("HEAD", path)
            return conn.getresponse().status
        except StandardError:
            return None
            
    print get_status_code("segmentfault.com") # prints 200
    print get_status_code("segmentfault.com", "/nonexistant") # prints 404

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  • 怪我咯
  • 怪我咯    2017-06-28 09:27:311楼

    你用get请求就会请求整个头部+正文, 可以试下head方法, 直接访问头部!

    import requests
    html = requests.head('http://segmentfault.com')    # 用head方法去请求资源头部
    print html.status_code  # 状态码
    
    html = requests.head('/nonexistant')   # 用head方法去请求资源头部
    print html.status_code   # 状态码
    
    # 输出:
    200
    404
    

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