Purpose: Remove the spaces to the right of the curly braces.
The following can be used:
//The first
var a = "I am a space {I am a parameter} There are spaces in front of me {I am a parameter} and the spaces in front of me do not match";
hand_trim1(a);
function hand_trim1(str){
return str.replace(/(?:\})\s+/g,'}');}
//Second
var a = "I am a space {I am a parameter}. There are spaces in front of me {I am a parameter}. The spaces in front of me do not match";
hand_trim2(a);
function hand_trim2(str){
return str.replace(/}\s+/g,'}');}
//The third one (Why doesn’t this match???????)
var a = "I am a space {I am a parameter} I am in front of {I It is a parameter} There are spaces. The spaces in front of me do not match ";
hand_trim3(a);
function hand_trim3(str){
return str.replace(/(?=\})\s+/g,'');}
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Forward preview is zero width, which means the width is 0, but matches a position, as long as the position is satisfied, and does not match specific content;
(?=})The matching position should be There is a}after this position;s+means that starting from this position, it will be followed by a blank character;So, the position that satisfies the above two conditions is that the character after this position is
}, and it isBlank character, therefore, this position does not exist at all, so it does not match;In fact, this position should be a
}on the left, ands+on the right, but js does not have a negative assertion, and the left side cannot be predicted character type.