python3.x - Problem with Python not operator

Question

{Code...} {Code...} As above, False will be calculated as 0 when operated directly. When using the logical operator not, the value of not(1) is False or 0. But why does not(1) directly enter the arithmetic operation and then the result of recalculation is False? This is similar to Python's algorithmic logic...

怪我咯 · Answer

Because not is not a function, but an expression. No matter you not(1)+5 or not (1+5), its function is just to invert the subsequent result. .
For example:

>>> not 1 + 2
False

>>> not (1 + 2)
False

>>> not (1 + 2) + 1
False

>>> (not (1 + 2)) + 1
1

漂亮男人 · Answer

Usage of not operator in Python Boolean Operations:

not x

if x is false, then True, else False

In addition, the precedence of the + operator is higher than that of the not operator, so in not(1) + 5, (1) + 5 is calculated first, and then (1)+5 serves as the operand of the not operator. For example, you can see:

not(-1)      # False
not(-1) + 1  # True

天蓬老师 · Answer

正如上面所说，因为 not operator 的优先级小于 +  
所以 not(1)+6 会被翻译为 not (1)+5
关于这些情况，你完全可以通过 dis模块 来查看具体的过程。

>>> import dis
>>> dis.dis("a = False + 5")
  1           0 LOAD_CONST               3 (5)
              3 STORE_NAME               0 (a)
              6 LOAD_CONST               2 (None)
              9 RETURN_VALUE
>>> dis.dis("a = not(1) + 5")
  1           0 LOAD_CONST               3 (6)
              3 UNARY_NOT
              4 STORE_NAME               0 (a)
              7 LOAD_CONST               2 (None)
             10 RETURN_VALUE