Equivalent writing of code.co_kwonlyargcount in Python2

Question

Suppose there is a piece of code like this: {code...} For Python3, we can get the keyword argument to be 0 through c.co_kwonlyargcount. For Python2, how to implement equivalent writing and get the corresponding key The number of word parameters.

滿天的星座 · Answer

https://docs.python.org/2/lib...

淡淡烟草味 · Answer

The number of parameters obtained by python2 and python3 is different:

def add(x, y):
    return x + y
    
python2:
c = add.func_code
c.co_argcount

python3:
c = add.__code__
c.co_argcount