// 随机生成数据
// let rand = () => Math.floor(Math.random() * 100)

// let arr = 'ABCDEFG'.split('').map(e => {
//     return {
//         name: e,
//         health: rand(),
//         experience: rand(),
//         security: rand(),
//     }
// })
// console.log(arr)

// 这是随机生成的一组数据
let arr = [ { name: 'A', health: 67, experience: 78, security: 88 },
  { name: 'B', health: 14, experience: 40, security: 32 },
  { name: 'C', health: 91, experience: 31, security: 64 },
  { name: 'D', health: 7, experience: 64, security: 26 },
  { name: 'E', health: 68, experience: 69, security: 77 },
  { name: 'F', health: 91, experience: 44, security: 43 },
  { name: 'G', health: 61, experience: 44, security: 68 } ]

// 排序
let ret = arr
    .sort((a, b) => {
        return b.health - a.health
    })
    .slice(0, 3)
    .sort((a, b) => {
        return b.experience - a.experience
    })
    .slice(0, 2)
    .sort((a, b) => {
        return b.security - a.security
    })
    .shift()

console.log(ret)
// { name: 'E', health: 68, experience: 69, security: 77 }

First of all, is this your topic or project? If it's a real project, you can use lodash 的 sortBy to sort the objects in the list.

Suppose your hotel list model simplifies to:

const list = [
  { name: 'foo', a: 3， b: 5, c: 7 }, // 这个是酒店模型，a, b, c就是各个因素的打分
  ...
]

The current requirement is to sort the objects in the list first by a, then by b, and then by c. To implement it is:

let result = _.sortBy(list, o = > o.a); // 先按a排序
result = _.sortBy(list, o => o.b);      // 再按b排序
result = _.sortBy(list, o => o.c);      // 最后按C排序

If the bigger the score, the better, then it should be in reverse order

let result = _.sortBy(list, o = > -o.a); // 先按a逆序排序
result = _.sortBy(list, o => -o.b);      // 再按b逆序排序
result = _.sortBy(list, o => -o.c);      // 再按c逆序排序

As mentioned in the question, if you want to pick out 3, 2, and 1, you don’t need to sort all the results every time.

let result = _.sortBy(list, o = > -o.a).slice(3);    // 排好序取三个
result = _.sortBy(list, o => -o.b).slice(2);
result = _.sortBy(list, o => -o.c).slice(1);
result[0]  // 第一名

If it is an interview question, you still need to complete sortBy这个函数， 可以简单利用Array#sortimplementation:

function sortBy(list, iterator) {
  return list.slice(0).sort(function(left, right) {
    left = iterator(left);
    right = iterator(right);
    return left < right ? -1 : 1;
  });
}

Note: sortBy要实现成稳定排序, 即两个分数一致的对象，排序前后相对位置要保持不变。
当然直接使用上Array#sort(func)This function is also very convenient.