python regular expression replacement

Question

Recently I encountered a regular expression replacement problem. Each piece of data in the time data is preceded by [0]= [1]= [2]= [3]= this index: {code...} Because of some reasons, the previous The index is gone and can only be added using regular expressions. The problem is that the amount of data in time is different {code...} There is...

黄舟 · Answer

>>> import re
>>> s='["time"]={{["status"]=true,["ac"]=1,["bg"]=2},{["status"]=true,["ac"]=1,["bg"]=2},{["status"]=true,["ac"]=1,["bg"]=2},}'
>>> n=0
>>> def repl(m):
    global n
    rslt='[%d]=%s'%(n,m.group(0))
    n+=1
    return rslt

>>> p=re.compile(r'\{[^{}]+\},')
>>> p.sub(repl,s)
'["time"]={[0]={["status"]=true,["ac"]=1,["bg"]=2},[1]={["status"]=true,["ac"]=1,["bg"]=2},[2]={["status"]=true,["ac"]=1,["bg"]=2},}'

曾经蜡笔没有小新 · Answer

i = 0
def func(x):
    global i
    s = '[%d]=%s' % (i,x)
    i += 1
    return s 
import re
a = '["time"]={{["status"]=true,["ac"]=1,["bg"]=2},{["status"]=true,["ac"]=1,["bg"]=2},}'
print re.sub('\{\["status"',lambda m:func(m.group(0)),a)

It’s not well written, it’s funny