python - Why does formatting with time.strftime use the default value?

Question

a = time.time()

time.sleep(3)

b = time.time()

time_consuming = time.strftime("%H:%M:%S", time.localtime(b - a))
print(time_consuming)

Use the above code to run time.strftime. After formatting the time, there is always a default value for the hour. How did this 8-hour default value come about?

迷茫 · Answer

Due to time zone issues, time should not be used, datetime.timedelta should be used to calculate
Refer to the code below

import time
import datetime

a = time.time()

time.sleep(3)

b = time.time()
print datetime.timedelta(seconds=(b -a ))  # <-- 推荐
time_consuming = time.strftime("%H:%M:%S", time.gmtime(b - a))  # <-- 不推荐
print(time_consuming)

The output is as follows:

0:00:03.004802
00:00:03

阿神 · Answer

8 hours is caused by time zone conversion: Beijing is the East Eighth District, and the time needs to be added forward by 8 hours.