python - Solving IP segmentation problem

Question

There is such an IP: "192.168.1.1-5,192.168.1.10-15" and I want it to be output as: 192.168.1.1192.168.1.2192.168.1.3192.168.1.4192.168.1.5192.168.1.10192.168.1.11192 .168.1.12192.168.1.13192 .168.1.14192.168.1.15 What's so good...

PHPz · Answer

a = "192.168.1.1-5,192.168.1.10-15"

# 根据逗号分隔不同的ip, 结果是一个列表[192.168.1.1-5, 192.168.1.10-15]
for ip in a.split(','):
    # ip就是遍历刚才的列表取得值, 根据.从右到左分割一次ip字符串, 获取结果192.168.1和1-5, 分别存给两个变量
    shuffix, _ = ip.rsplit('.', 1)
    # 用-切分1-5, 得出一个范围区间
    start, end = map(int, _.split('-'))
    for num in range(start, end+1):
        # num为上述范围区间的数, 然后拼接一开始的字符串, 组成新ip
        print('{}.{}'.format(shuffix, num))

过去多啦不再A梦 · Answer

# coding: utf-8

import os

str = '192.168.1.1-5,192.168.1.10-15'

for x in str.split(','):
    _, y = os.path.splitext(x)
    start, end = y.replace('.', '').split('-')
    for i in range(int(start), int(end) + 1):
        print '{}.{}'.format(_, i)