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Check if a C/C++ program divisible by 3 can be constructed using all the numbers in an array
Article Introduction:To check if a number is divisible by 3, we add all the digits of the number and then calculate whether the sum is divisible by 3. In this problem, there is an array of integers arr[] and we need to check whether the number consisting of these numbers is divisible by 3. If it is divisible, print 'yes', otherwise print 'no'. Input:arr[]={45,51,90}Output:Yes explanation constructs a number that can be divisible by 3, such as 945510. So the answer will be yes, when divisible by 3, the remainder of the sum is 0. Example#include<stdio.h&
2023-09-17
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1603
Java program to check if a number is divisible by 5
Article Introduction:Introduction This program is a simple Java program that checks whether the number entered by the user is divisible by 5. The program prompts the user for a number, uses the Scanner class to read the input, and then uses the modulo operator % to check whether the number is divisible by 5. If the remainder of the division is 0, then the number is divisible by 5, and the program prints a message to the console indicating this. If the remainder is not 0, then the number is not divisible by 5, and the program also prints a message to the console to indicate this. The program uses basic Java concepts such as variables, user input, conditional statements, and console output. It also demonstrates how to use the Scanner class to read user input from the console. Commonly used primitive data types in writing
2023-09-11
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1739
Check if it is possible to make a C/C++ program divisible by 3 using all the numbers in the array
Article Introduction:In this section we will see if an array contains n numbers, we have to check if using all the elements of these numbers we generate a number that is divisible by 3. If the array elements are {15,24,23,13} then we can make an integer like 15242313. is divisible by 3. Algorithm checkDivThree(arr)Begin rem:=0 forachelementeinarr,do rem:=(rem+e)mod3
2023-09-05
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1419
Java program to check if a number is divisible by 5
Article Introduction:In mathematics, the divisibility rule of 5 states that if a number ends in 0 or 5, it is divisible by 5. There is another way to determine the divisibility rule of 5, if the remainder is 0, then return the number divisible by 5. The mod(%) operator is commonly used in programming for integer division. Let's give an example. The given number is 525, the number ends with 5 and is divisible by 5. The given number is 7050 which ends with 0 and is divisible by 5. The given number is 678 which does not end with 0 and 5 and is not divisible by 5. In this article, we will solve the question of whether the number is divisible by 5. Algorithm The following steps are where we will use the java.util.* packages to get user input of primitive data types. from main class
2023-09-13
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1617
C program to check if a number is divisible by the sum of its digits
Article Introduction:Given a number n, we need to check whether the sum of its digits is divisible by n. To find out, we need to add all the numbers starting from the ones digit and then divide the final sum by that number. For example, we have a number "521", and we need to find the sum of its digits, that is, "5+2+1=8", but 521 cannot be divided by 8, and the remainder is not 0. For another example, "60", the sum of its digits is "6+0=6", 6 can divide 60, and the remainder is 0. ExampleInput:55Output:NoExplanation:5+5=10;55notdiv
2023-08-30
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1591
C program to check if all the digits of a number can divide it
Article Introduction:For a given number n, we need to find out if all the digits of n are divisible by it, i.e. if a number is 'xy', then both x and y should be divisible by it. Example Input - 24 Output - Yes Explanation - 24%2==0,24%4==0 Use conditional statements to check whether each number is non-zero and divisible. We need to iterate over each number and check if that number is divisible by the given number. Example #include<stdio.h>intmain(){ intn=24; &
2023-09-19
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1089
Check if there is any valid sequence divisible by M
Article Introduction:A sequence is a collection of objects, in our case it is a collection of integers. The task is to determine whether the sequence using addition and subtraction operators within the elements is divisible by M. Problem StatementGiven an integer M and an array of integers. Check whether there is a valid sequence whose solution is divisible by M using only addition and subtraction between elements. Example 1Input:M=2,arr={1,2,5}Output:TRUE Explanation - For the given array, there may be a valid sequence {1+2+5}={8}, which is divisible by 2. Example 2Input:M=4,arr={1,2}Output:FALSE Explanation - For the given array, there cannot be a sequence whose solution is divisible by 4. Method 1: Violent method to solve the problem
2023-09-11
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857