java如何实现获取字符串中第一个出现不重复的字符

import java.util.Scanner;
public class Main
{
  public static void main(String[] args)
  {
    Scanner in = new Scanner(System.in);
    String str = in.next();
    for(int i =0 ; i < str.length() ; i++)
    {
      if(str.lastIndexOf(str.char(i)) == i && 
      str.indexOf(str.char(i)) == i)
      {
        System.out.println(str.char(i));
        break;
      }
    }
  }
}

import java.util.Scanner;
public class Main
{
  public static void main(String[] args)
  {
    Scanner in = new Scanner(System.in);
    String str = in.next();
    char[] cb = new char[str.length()];
    //将字符串中的字符一次存入cb[]
    for(int i =0 ;i <str.length() ; i++)
    {
      cb[i] = str.charAt(i);
    }
    for(int i = 0 ; i < str.length() ; i++)
    {
      for(int j = 0 ; j < str.length() ; j++)
      {
        if(cb[i] == cb[j] && cb[i] != &#39;0&#39;)
        {
          char c = cb[i];
          for(int z = 0 ; z < str.length() ; z++)
          {
            if(cb[z] == c)
              cb[z] = &#39;0&#39;;
          }
        }
      }
    }
    for(int i = 0 ; i <str.length() ; i++)
    {
      if(cb[i] != &#39;0&#39;)
      {
        System.out.println(cb[i]);
        break;
      }
    }
  }
}