How to read txt data file into matrix in Python3

Below I will share with you a method of reading txt data files into a matrix in Python3. It has a good reference value and I hope it will be helpful to everyone. Let’s take a look together

1. Example program:

'''
数据文件：2.txt内容：（以空格分开每个数据）
1 2 2.5
3 4 4
7 8 7
'''

from numpy import *
A = zeros((3,3),dtype=float)  #先创建一个 3x3的全零方阵A，并且数据的类型设置为float浮点型

f = open('2.txt')        #打开数据文件文件
lines = f.readlines()      #把全部数据文件读到一个列表lines中
A_row = 0            #表示矩阵的行，从0行开始
for line in lines:       #把lines中的数据逐行读取出来
  list = line.strip('\n').split(' ')   #处理逐行数据：strip表示把头尾的'\n'去掉，split表示以空格来分割行数据，然后把处理后的行数据返回到list列表中
  A[A_row:] = list[0:3]          #把处理后的数据放到方阵A中。list[0:3]表示列表的0,1,2列数据放到矩阵A中的A_row行
  A_row+=1                #然后方阵A的下一行接着读
  #print(line)

print(A)  #打印 方阵A里的数据

打印结果：
[[ 1.  2.  2.5]
 [ 3.  4.  4. ]
 [ 7.  8.  7. ]]

2. The logic of reading data into the matrix:

is a simple explanation. For example, we need to:

1 2 3

4 5 6

7 8 9

Read into the matrix, take the above code as an example:

When When A_row =0, after executing A[A_row:] = list[0:3], the matrix A is:

When A_row = 1, execute A[A_row:] = list[0:3] after matrix A Is:

What

for line in lines:           #先把逐行数据取出来 
  list = line.strip('\n').split(' ')   #再通过处理，放回到list列表中 
  A[A_row:] = list[0:3]          #然后把list列表的数据放到矩阵中 
  A_row+=1

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