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How to convert python numbers to Chinese: 1. Convert Arabic numerals into Chinese through the "def num_to_char(num)..." method; 2. Convert Arabic numerals into Chinese through the "def _to_chinese4(num)..." method Just convert the numbers into corresponding Chinese.
The operating environment of this article: windows7 system, DELL G3 computer, python3.5 version
Python realizes the conversion of Arabic numerals into Chinese
The first conversion method:
1 --> 一 12 --> 一二 def num_to_char(num): """数字转中文""" num=str(num) new_str="" num_dict={"0":u"零","1":u"一","2":u"二","3":u"三","4":u"四","5":u"五","6":u"六","7":u"七","8":u"八","9":u"九"} listnum=list(num) # print(listnum) shu=[] for i in listnum: # print(num_dict[i]) shu.append(num_dict[i]) new_str="".join(shu) # print(new_str) return new_str
The second conversion method:
1 --> 一 12 --> 十二 23 --> 二十三 _MAPPING = (u'零', u'一', u'二', u'三', u'四', u'五', u'六', u'七', u'八', u'九', u'十', u'十一', u'十二', u'十三', u'十四', u'十五', u'十六', u'十七',u'十八', u'十九') _P0 = (u'', u'十', u'百', u'千',) _S4 = 10 ** 4 def _to_chinese4(num): assert (0 <= num and num < _S4) if num < 20: return _MAPPING[num] else: lst = [] while num >= 10: lst.append(num % 10) num = num / 10 lst.append(num) c = len(lst) # 位数 result = u'' for idx, val in enumerate(lst): val = int(val) if val != 0: result += _P0[idx] + _MAPPING[val] if idx < c - 1 and lst[idx + 1] == 0: result += u'零' return result[::-1]
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