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Talk about the problem of implementing AST abstract syntax tree in JS

coldplay.xixiforward: 2021-02-19 17:45:212449browse

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AST abstract syntax tree problem in the front end

Four arithmetic operations
Regular expression
Lexical analysis
Syntax analysis
Complete code

Four Arithmetic Operations

First of all, it is clear that the code this time is based on LL syntax analysis. It implements the function of the four arithmetic mixed operations. Let’s look at the definition first:
TokenNumber:
· 1 2 3 4 5 6 7 8 9 0 combination
Operator:
- * / One of
WhiteSpace:
<sp></sp>
LineTerminator:
<lf></lf> <cr></cr>

Look at the production:
Talk about the problem of implementing AST abstract syntax tree in JS

##Regular Expression

We first implement the matching principle of regular expressions:

<script>
    var regexp = /([0-9\.]+)|([ \t]+)|([\r\n]+)|(\*)|(\/)|(\+)|(\-)/g

    var dictionary = ["Number", "Whitespace", "LineTerminator", "*", "/", "+", "-"];

    function tokenize(source) {
        var result = null;
        while(true) {
            result = regexp.exec(source);

            if(!result) break;

            for(var i = 1; i <= dictionary.length; i ++) {
                if(result[i])
                    console.log(dictionary[i - 1]);
            }
            console.log(result);
        }
    }

    tokenize("1024 + 10 * 25");</script>

At this time we take a look at the running print results of the page:

Talk about the problem of implementing AST abstract syntax tree in JS It is worth mentioning that The exec method is used here. The exec() method is used to retrieve regular expression matches in a string.
Let's take a look at its syntax:

RegExpObject.exec(string)

If exec() finds matching text, it returns an array of results. Otherwise, returns null. The 0th element of this array is the text that matches the regular expression, the 1st element is the text that matches the 1st subexpression of RegExpObject (if any), and the 2nd element is the text that matches the 1st subexpression of RegExpObject The text matched by 2 subexpressions (if any), and so on. In addition to the array elements and length properties, the exec() method returns two properties. The index attribute declares the position of the first character of the matching text. The input attribute stores the retrieved string string. We can see that when the exec() method of the non-global RegExp object is called, the array returned is the same as the array returned by the String.match() method.

However, when RegExpObject is a global regular expression, the behavior of exec() is slightly more complicated. It starts retrieving the string string at the character specified by the RegExpObject's lastIndex property. When exec() finds text that matches an expression, it sets the RegExpObject's lastIndex property to the position next to the last character of the matching text after the match. This means that you can iterate over all matching text in a string by calling the exec() method repeatedly. When exec() no longer finds matching text, it returns null and resets the lastIndex property to 0.

Lexical analysis

We optimize the above code in this part.

First of all, what was just mentioned:

When RegExpObject is a global regular expression, the behavior of exec() is slightly more complicated. It starts retrieving the string string at the character specified by the RegExpObject's lastIndex property. When exec() finds text that matches an expression, it sets the RegExpObject's lastIndex property to the position next to the last character of the matching text after the match. Then we have to consider the situation where there is no matching character and make a judgment:

<script>
    var regexp = /([0-9\.]+)|([ \t]+)|([\r\n]+)|(\*)|(\/)|(\+)|(\-)/g

    var dictionary = ["Number", "Whitespace", "LineTerminator", "*", "/", "+", "-"];

    function* tokenize(source) {
        var result = null;
        var lastIndex = 0;
        while(true) {
            lastIndex = regexp.lastIndex;
            result = regexp.exec(source);

            if(!result) break;

            if(regexp.lastIndex - lastIndex > result[0].length)
                break;
            
            let token = {
                type: null,
                value: null
            }

            for(var i = 1; i <= dictionary.length; i ++) {
                if(result[i])
                    token.type = dictionary[i - 1];
            }
            token.value = result[0];
            yield token        }
        yield {
            type: &#39;EOF&#39;
        }
    }

    for (let token of tokenize("1024 + 10 * 25")) {
        console.log(token)
    }</script>

As above, we have

regexp.lastIndex - lastIndex and The length of result[0] is compared to determine whether any string does not match. Change the entire function into the form of a generator function. Let’s look at the results of the operation:

Talk about the problem of implementing AST abstract syntax tree in JS

Syntax analysis

First write the chunks Production, let's take a look at the overall code structure:

<script>
    var regexp = /([0-9\.]+)|([ \t]+)|([\r\n]+)|(\*)|(\/)|(\+)|(\-)/g

    var dictionary = ["Number", "Whitespace", "LineTerminator", "*", "/", "+", "-"];

    function* tokenize(source) {
        var result = null;
        var lastIndex = 0;
        while(true) {
            lastIndex = regexp.lastIndex;
            result = regexp.exec(source);

            if(!result) break;

            if(regexp.lastIndex - lastIndex > result[0].length)
                break;
            
            let token = {
                type: null,
                value: null
            }

            for(var i = 1; i <= dictionary.length; i ++) {
                if(result[i])
                    token.type = dictionary[i - 1];
            }
            token.value = result[0];
            yield token        }
        yield {
            type: &#39;EOF&#39;
        }
    }

    let source = [];

    for(let token of tokenize("10 * 25")) {
        if (token.type !== "Whitespace" && token.type !== "LineTerminator")
            source.push(token);
    }

    function Expression(tokens) {

    }

    function AdditiveExpression(source){

    }

    function MultiplicativeExpresson(source) {
        console.log(source);
    }

    MultiplicativeExpresson("10 * 25")</script>

Let's study it first from

MultiplicativeExpresson, which is divided into four situations:

function MultiplicativeExpresson(source) {
	//如果是数字则进行封装
     if(source[0].type === "Number") {
         let node = {
             type: "MultiplicativeExpresson",
             children:[source[0]]
         }
         source[0] = node;
         return MultiplicativeExpresson(source)
     }

     //如果是乘号或者除号，则将三项出栈，进行重组
     if(source[0].type === "MultiplicativeExpresson" && source[1] && source[1].type === "*") {
         let node = {
             type: "MultiplicativeExpresson",
             operator: "*",
             children: []
         }
         node.children.push(source.shift());
         node.children.push(source.shift());
         node.children.push(source.shift());
         source.unshift(node);
         return MultiplicativeExpresson(source)
     }

     if(source[0].type === "MultiplicativeExpresson" && source[1] && source[1].type === "/") {
         let node = {
             type: "MultiplicativeExpresson",
             operator: "*",
             children: []
         }
         node.children.push(source.shift());
         node.children.push(source.shift());
         node.children.push(source.shift());
         source.unshift(node);
         return MultiplicativeExpresson(source)
     }

     //递归结束的条件
     if(source[0].type === "MultiplicativeExpresson")
         return source[0];

     return MultiplicativeExpresson(source);
 }

Let's take a look When the source is

"10 * 25 / 2", call console.log(MultiplicativeExpresson(source))The final running result:
Talk about the problem of implementing AST abstract syntax tree in JS Let’s see next
AdditiveExpression is essentially the same as MultiplicativeExpresson. The differences have been marked in the code:

    function AdditiveExpression(source){
        if(source[0].type === "MultiplicativeExpresson") {
            let node = {
                type: "AdditiveExpression",
                children:[source[0]]
            }
            source[0] = node;
            return AdditiveExpression(source)
        }

        //如果是乘号或者除号，则将三项出栈，进行重组
        if(source[0].type === "AdditiveExpression" && source[1] && source[1].type === "+") {
            let node = {
                type: "AdditiveExpression",
                operator: "+",
                children: []
            }
            node.children.push(source.shift());
            node.children.push(source.shift());
            //考虑到第三个数可能时Number 需要在这里再次调用一下 MultiplicativeExpresson 做处理
            MultiplicativeExpresson(source);
            node.children.push(source.shift());
            source.unshift(node);
            return AdditiveExpression(source)
        }

        if(source[0].type === "AdditiveExpression" && source[1] && source[1].type === "-") {
            let node = {
                type: "AdditiveExpression",
                operator: "-",
                children: []
            }
            node.children.push(source.shift());
            node.children.push(source.shift());
            MultiplicativeExpresson(source);
            node.children.push(source.shift());
            source.unshift(node);
            return AdditiveExpression(source)
        }

        //递归结束的条件
        if(source[0].type === "AdditiveExpression")
            return source[0];

        //第一次进循环 调用
        MultiplicativeExpresson(source);
        return AdditiveExpression(source);
    }

我们看一下当source为"10 * 25 / 2"时调用console.log(AdditiveExpression(source))最后运行的结果：
Talk about the problem of implementing AST abstract syntax tree in JS
那么Expression的代码逻辑就很好表达了：

function Expression(tokens) {
     if(source[0].type === "AdditiveExpression" && source[1] && source[1].type === "EOF") {
         let node = {
             type: "Expression",
             children: [source.shift(), source.shift()]
         }
         source.unshift(node);
         return node;
     }
     AdditiveExpression(source);
     return Expression(source);
 }

看下运行后的结果：
Talk about the problem of implementing AST abstract syntax tree in JS
以上就是所有的js解析抽象语法树的代码。

完整代码

<script>
    var regexp = /([0-9\.]+)|([ \t]+)|([\r\n]+)|(\*)|(\/)|(\+)|(\-)/g

    var dictionary = ["Number", "Whitespace", "LineTerminator", "*", "/", "+", "-"];

    function* tokenize(source) {
        var result = null;
        var lastIndex = 0;
        while(true) {
            lastIndex = regexp.lastIndex;
            result = regexp.exec(source);

            if(!result) break;

            if(regexp.lastIndex - lastIndex > result[0].length)
                break;
            
            let token = {
                type: null,
                value: null
            }

            for(var i = 1; i <= dictionary.length; i ++) {
                if(result[i])
                    token.type = dictionary[i - 1];
            }
            token.value = result[0];
            yield token        }
        yield {
            type: &#39;EOF&#39;
        }
    }

    let source = [];

    for(let token of tokenize("10 * 25 / 2")) {
        if (token.type !== "Whitespace" && token.type !== "LineTerminator")
            source.push(token);
    }

    function Expression(tokens) {
        if(source[0].type === "AdditiveExpression" && source[1] && source[1].type === "EOF") {
            let node = {
                type: "Expression",
                children: [source.shift(), source.shift()]
            }
            source.unshift(node);
            return node;
        }
        AdditiveExpression(source);
        return Expression(source);
    }

    function AdditiveExpression(source){
        if(source[0].type === "MultiplicativeExpresson") {
            let node = {
                type: "AdditiveExpression",
                children:[source[0]]
            }
            source[0] = node;
            return AdditiveExpression(source)
        }

        //如果是乘号或者除号，则将三项出栈，进行重组
        if(source[0].type === "AdditiveExpression" && source[1] && source[1].type === "+") {
            let node = {
                type: "AdditiveExpression",
                operator: "+",
                children: []
            }
            node.children.push(source.shift());
            node.children.push(source.shift());
            //考虑到第三个数可能时Number 需要在这里再次调用一下 MultiplicativeExpresson 做处理
            MultiplicativeExpresson(source);
            node.children.push(source.shift());
            source.unshift(node);
            return AdditiveExpression(source)
        }

        if(source[0].type === "AdditiveExpression" && source[1] && source[1].type === "-") {
            let node = {
                type: "AdditiveExpression",
                operator: "-",
                children: []
            }
            node.children.push(source.shift());
            node.children.push(source.shift());
            MultiplicativeExpresson(source);
            node.children.push(source.shift());
            source.unshift(node);
            return AdditiveExpression(source)
        }

        //递归结束的条件
        if(source[0].type === "AdditiveExpression")
            return source[0];

        //第一次进循环 调用
        MultiplicativeExpresson(source);
        return AdditiveExpression(source);
    }

    function MultiplicativeExpresson(source) {
        if(source[0].type === "Number") {
            let node = {
                type: "MultiplicativeExpresson",
                children:[source[0]]
            }
            source[0] = node;
            return MultiplicativeExpresson(source)
        }

        //如果是乘号或者除号，则将三项出栈，进行重组
        if(source[0].type === "MultiplicativeExpresson" && source[1] && source[1].type === "*") {
            let node = {
                type: "MultiplicativeExpresson",
                operator: "*",
                children: []
            }
            node.children.push(source.shift());
            node.children.push(source.shift());
            node.children.push(source.shift());
            source.unshift(node);
            return MultiplicativeExpresson(source)
        }

        if(source[0].type === "MultiplicativeExpresson" && source[1] && source[1].type === "/") {
            let node = {
                type: "MultiplicativeExpresson",
                operator: "*",
                children: []
            }
            node.children.push(source.shift());
            node.children.push(source.shift());
            node.children.push(source.shift());
            source.unshift(node);
            return MultiplicativeExpresson(source)
        }

        //递归结束的条件
        if(source[0].type === "MultiplicativeExpresson")
            return source[0];

        return MultiplicativeExpresson(source);
    }

    console.log(Expression(source))</script>

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