Get value in url in FormRequest form validator

The following column will introduce to you how to get the value in the url in the FormRequest form validator from the Laravel Tutorial column. I hope it will be helpful to friends in need!

I recently started a blog and wrote "elegant" code according to the Laravel project development specifications.
The routing of the project is probably like this

Route::get('/keywords','KeywordsController@index');
Route::get('/keywords/create','KeywordsController@create');
Route::post('/keywords/store','KeywordsController@store');
Route::delete('/keywords/{id}','KeywordsController@destory');
Route::get('/keywords/{id}/edit','KeywordsController@edit');
Route::put('/keywords/{id}','KeywordsController@update');

The validator uses the FormRequest base class to verify. The code is as follows

5705b8bddb444eeb674bbbff5cf462dfroute('id') 获取url占位符为id的数据
        switch ($this->method())
        {
            case  'POST' :
            {
                return [
                  'keyword' => 'required|unique:keywords'
                ];
            }
            case 'PUT':
            case 'PATCH':
            {
              return [
                'keyword' => [
                  'required',
                  Rule::unique('keywords')->ignore($this->route('id')),
                ],
              ];
            }
            case 'DELETE':
            case 'GET':
            default:
            {
                return [];
            }
        }
    }
    public function messages()
    {
       return [
           'keyword.required' => '关键字不能为空',
           'id.required' => 'id不能为空',
           'keyword.unique' => '关键字已存在,请重新填写'
       ];
    }}

Verification is performed according to the request method
In order to maintain the standard, when I updated the request, I did not put the id in the form, but only in the URL. There is also such a method in the official documents.

use Illuminate\Validation\Rule;
Validator::make($data, [
    'email' => [
        'required',
        Rule::unique('users')->ignore($user->id),
    ],]);

But I never knew how to get this $user->id. I finally found a method online that met my requirements

$this->route('id')

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