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How to delete specified elements from js arrays: First define a function for the js array object to find the position of the specified element in the array, that is, the index; then use the corresponding function through the obtained index of the specified element to delete the specified element.
First, you can define a function for the JS array object to find the position of the specified element in the array, that is, the index. The code is:
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Array.prototype.indexOf = function(val) { for (var i = 0; i < this.length; i++) { if (this[i] == val) return i; } return -1; };
Then use the index of the element to get the index, and use the js array's own inherent function to delete the element:
The code is:
Array.prototype.remove = function(val) { var index = this.indexOf(val); if (index > -1) { this.splice(index, 1); } };
In this way, such a function is constructed. For example, I have an array:
var emp = ['abs','dsf','sdf','fd']
If we want to delete the 'fd' in it, we can use:
emp.remove('fd');
Delete an item of the array
splice(index,len,[item]) Note: This method will change the original array.
splice has 3 parameters, it can also be used to replace/delete/add one or several values in the array
index: array starting subscript len: replacement/delete length item :Replacement value, if the delete operation is performed, the item will be empty
For example: arr = ['a','b','c','d']
Delete
//删除起始下标为1,长度为1的一个值(len设置1,如果为0,则数组不变) var arr = ['a','b','c','d']; arr.splice(1,1); console.log(arr); //['a','c','d']; //删除起始下标为1,长度为2的一个值(len设置2) var arr2 = ['a','b','c','d'] arr2.splice(1,2); console.log(arr2); //['a','d']
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