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How to replace whitespace in php: first remove the starting and ending whitespace through the "trim($str)" method; then use "preg_replace" to remove the whitespace that is crowded with others; finally use regular expressions to remove non-space blank and replace it with a space.
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php replaces and filters all whitespace characters and spaces Example
The trim function that comes with PHP can only replace the spaces at the left and right ends. I feel that it is not very useful in some cases. If you want to filter out all the whitespace characters in a string (spaces , full-width spaces, newlines, etc.), then we can write a filter function ourselves.
Everyone who has learned the str_replace function in php knows that it can be replaced in batches, so we can use the following source code to replace and filter all whitespace characters in a string.
php source code reference:
$str = 'jkgsd gsgsdgs gsdg gsd'; echo myTrim($str); function myTrim($str) { $search = array(" "," ","\n","\r","\t"); $replace = array("","","","",""); return str_replace($search, $replace, $str); } ?> 运行代码,页面输出:jkgsdgsgsdgsgsdggsd,完美实现了我们想要的效果。 完成这些可以使用PHP的正则表达式来完成 下例可以去除额外Whitespace $str = " This line contains\tliberal \r\n use of whitespace.\n\n"; // First remove the leading/trailing whitespace //去掉开始和结束的空白 $str = trim($str); // Now remove any doubled-up whitespace //去掉跟随别的挤在一块的空白 $str = preg_replace('/\s(?=\s)/', '', $str); // Finally, replace any non-space whitespace, with a space //最后,去掉非space 的空白,用一个空格代替 $str = preg_replace('/[\n\r\t]/', ' ', $str); // Echo out: 'This line contains liberal use of whitespace.' echo " {$str} "; ?> 这个例子剥离多余的空白字符 $str = 'foo o'; $str = preg_replace('/\s\s+/', '', $str); // 将会改变为'foo o' echo $str; ?>
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