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How to implement a simple Socket in PHP

Guanhui
GuanhuiOriginal
2020-05-13 13:55:423205browse

How to implement a simple Socket in PHP

PHP如何实现简单的Socket

首先使用PHP制作的Socket服务端,其主要是设置Socket的IP地址及端口号;然后监听端口,如果有客户端连接的话,则接收连接请求和数据,最后处理数据并且返回数据即可。

示例代码:

<?php
//确保在连接客户端时不会超时
set_time_limit(0);
//设置IP和端口号
$address = "127.0.0.1";
$port = 2048; //调试的时候,可以多换端口来测试程序!
/**
 * 创建一个SOCKET 
 * AF_INET=是ipv4 如果用ipv6,则参数为 AF_INET6
 * SOCK_STREAM为socket的tcp类型,如果是UDP则使用SOCK_DGRAM
*/
$sock = socket_create(AF_INET, SOCK_STREAM, SOL_TCP) or die("socket_create() 失败的原因是:" . socket_strerror(socket_last_error()) . "/n");
//阻塞模式
socket_set_block($sock) or die("socket_set_block() 失败的原因是:" . socket_strerror(socket_last_error()) . "/n");
//绑定到socket端口
$result = socket_bind($sock, $address, $port) or die("socket_bind() 失败的原因是:" . socket_strerror(socket_last_error()) . "/n");
//开始监听
$result = socket_listen($sock, 4) or die("socket_listen() 失败的原因是:" . socket_strerror(socket_last_error()) . "/n");
echo "OK\nBinding the socket on $address:$port ... ";
echo "OK\nNow ready to accept connections.\nListening on the socket ... \n";
do { // never stop the daemon
 //它接收连接请求并调用一个子连接Socket来处理客户端和服务器间的信息
 $msgsock = socket_accept($sock) or die("socket_accept() failed: reason: " . socket_strerror(socket_last_error()) . "/n");
 
 //读取客户端数据
 echo "Read client data \n";
 //socket_read函数会一直读取客户端数据,直到遇见\n,\t或者\0字符.PHP脚本把这写字符看做是输入的结束符.
 $buf = socket_read($msgsock, 8192);
 echo "Received msg: $buf \n";
 
 //数据传送 向客户端写入返回结果
 $msg = "welcome \n";
 socket_write($msgsock, $msg, strlen($msg)) or die("socket_write() failed: reason: " . socket_strerror(socket_last_error()) ."/n");
 //一旦输出被返回到客户端,父/子socket都应通过socket_close($msgsock)函数来终止
 socket_close($msgsock);
} while (true);
socket_close($sock);

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