How to return array from function in c++

#c How to return an array from a function?

C Returning an array from a function

C Returning a complete array as a function parameter is not allowed. However, you can return a pointer to an array by specifying the array name without an index.

If you want to return a one-dimensional array from a function, you must declare a function that returns a pointer, as follows:

int * myFunction()
{
.
.
.
}

In addition, C does not support returning the address of a local variable outside a function. Unless local variables are defined as static variables.

Now, let us look at the following function, which will generate 10 random numbers and return them using an array, as follows:

Example

#include <iostream>
#include <cstdlib>
#include <ctime>
 
using namespace std;
 
// 要生成和返回随机数的函数
int * getRandom( )
{
  static int  r[10];
 
  // 设置种子
  srand( (unsigned)time( NULL ) );
  for (int i = 0; i < 10; ++i)
  {
    r[i] = rand();
    cout << r[i] << endl;
  }
 
  return r;
}
 
// 要调用上面定义函数的主函数
int main ()
{
   // 一个指向整数的指针
   int *p;
 
   p = getRandom();
   for ( int i = 0; i < 10; i++ )
   {
       cout << "*(p + " << i << ") : ";
       cout << *(p + i) << endl;
   }
 
   return 0;
}

When the above When the code is compiled and executed, it produces the following results:

624723190
1468735695
807113585
976495677
613357504
1377296355
1530315259
1778906708
1820354158
667126415
*(p + 0) : 624723190
*(p + 1) : 1468735695
*(p + 2) : 807113585
*(p + 3) : 976495677
*(p + 4) : 613357504
*(p + 5) : 1377296355
*(p + 6) : 1530315259
*(p + 7) : 1778906708
*(p + 8) : 1820354158
*(p + 9) : 667126415

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